- #1
assassin___0
- 1
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As the title says, is it possible? I was thinking that in order for the multimeter to measure resistance, it first provides current and checks the voltage, and then by ohm's law gets the resistance.
But would it even be possible to provide current to n-type Si bar or p-type Si bar? I know that in the diode, when the positive and negative leads are connected to p-type and n-type respectively, you can provide current. But what's going to happen if both positive and negative are connected to just n-type or just p-type?
But would it even be possible to provide current to n-type Si bar or p-type Si bar? I know that in the diode, when the positive and negative leads are connected to p-type and n-type respectively, you can provide current. But what's going to happen if both positive and negative are connected to just n-type or just p-type?