MHB Is Limsup of Upper Semicontinuous Function True? Help Needed

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The discussion centers on whether the limit superior (limsup) of an upper semicontinuous function equals the limit of the function itself. A participant argues that this is not true by providing the example of the continuous function f(x) = sin(x), which has a limsup of 1 as x approaches infinity. The example illustrates that the limsup can differ from the limit of the function. The conversation highlights the need for clarification on the properties of upper semicontinuous functions. Overall, the claim that limsup f(x) equals lim f(x) for upper semicontinuous functions is contested.
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for any upper semicontinuous function limsup f(x)=lim f(x)...Is thıs true ? I don't know, please help me :)
 
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No,

Just think in $f(x)=sin(x)$, is continuous and its upper limit is 1 when $x\to +\infty$
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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