- #1
jkristia
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I'm still trying to figure out how to do limits of trig functions and I would like to know if this is the correct approach. I know the answer is correct, but not sure if that is just a coincidence.
lim (x -> 0) of (sin 2x) / (sin3x).
First I try to get the equation into the form (sin x) / x or x / (sin x)
so I multiply by
(x/x)(3/3)(2/2)
this gives me
(1/3)(3x/sin3x)(2/1)(sin2x/2x)
so I get
(1/3)(1)(2/1)(1) = 2/3
Is that the correct approach?
Homework Statement
lim (x -> 0) of (sin 2x) / (sin3x).
Homework Equations
The Attempt at a Solution
First I try to get the equation into the form (sin x) / x or x / (sin x)
so I multiply by
(x/x)(3/3)(2/2)
this gives me
(1/3)(3x/sin3x)(2/1)(sin2x/2x)
so I get
(1/3)(1)(2/1)(1) = 2/3
Is that the correct approach?