- #1
noppawit
- 27
- 0
A rigid body is made of three identical thin rods, each with length L=0.60m, fastened together together in the form of a letter H. The body is free to rotate about a horizontal axis that runs along the length of one of the legs of H. The body is allowed to fall from rest from a position in which the plane of the H is horizontal. What is the angular speed of the body when the plane of the H is vertical?
I am quite not sure that can I change g (gravity) to α (Angular acceleration) by using gr = α
For my solution,
α (Angular acceleration) = g/r = 9.81/0.6 = 16.4 rad/s2
θ = 90 radian, as it said fall from plane of the H is horizontal to H is vertical.
ω2 = ω02+2aθ
ω2 = 0 + 2(16.4)(90)
Answer is 54.3 rad/s
Am I all correct? I'm quite not sure especially angular acceleration.
Thank you
I am quite not sure that can I change g (gravity) to α (Angular acceleration) by using gr = α
For my solution,
α (Angular acceleration) = g/r = 9.81/0.6 = 16.4 rad/s2
θ = 90 radian, as it said fall from plane of the H is horizontal to H is vertical.
ω2 = ω02+2aθ
ω2 = 0 + 2(16.4)(90)
Answer is 54.3 rad/s
Am I all correct? I'm quite not sure especially angular acceleration.
Thank you