MHB Is My Solution to These Set Operations Correct?

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The discussion focuses on verifying the correctness of set operations involving the universal set U and subsets A, B, C, and D. The user calculates B' ∪ D' and A' ∪ B', concluding that B' ∪ D' equals the universal set U. They also find that A' ∩ B' results in the set D. The responses confirm that the user's calculations are accurate. Overall, the solution presented is correct.
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just want to make sure if my answer is correct

If $\displaystyle U\,=\,\{0,\,1,\,2,\,3,\,4,\,5,\,6,\,7,\,8,\,9\}$, the set of digits in our decimal system, and $\displaystyle A\,=\,\{0,\,1,\,2,\,3,\,4,\,5\}$, $\displaystyle B\,=\,\{2,\,3,\,4,\,5,\}$, $\displaystyle C\,=\,\{4,\,5,\,6,\,7\}$, $\displaystyle D\,=\,\{6,\,7,\,8,\,9\}$, find and tabulate:

a. $\displaystyle B'\,\cup\,D'$
b. $\displaystyle A'\,\cup\,B'$

here's my solution

$\displaystyle B'\,\cup\,D'\,=\,\{0,\,1,\,6,\,7,\,8,\,9\}\cup\{0,\,1,\,2,\,3,\,4,\,5,\}\,=\,U$
$\displaystyle A'\,\cap\,B'\,=\,\{6,\,7,\,8,\,9\}\cap\{0,\,1,\,6,\,7,\,8,\,9\}\,=\,\{\,6,\,7,\,8,\,9\}\,=\,D$
 
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Re: Operations on set II

Looks good to me! (Sun)
 
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