- #1
Denver Dang
- 148
- 1
Homework Statement
Hi...
I got a problem where I'm asked to figure out if several decays is forbidden or not.
One says:
[itex]p \rightarrow e^{+} + \gamma[/itex]
I'm then thinking baryon number conservation, but I'm not quite sure if it is right.
The proton, p, is a baryon made up of 3 quarks, and the positron and photon is elemental particles, which isn't made up of any quarks. So my question, even though it sounds quite simple, just wanted to be sure, is, do they count as zero, and therefore means that I get 1 = 0, which violates the baryon number conservation, or am I mistaken ?
Regards