Is Q a Subspace of R2 or R3?

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In summary, the conversation was about determining whether a given subset Q is a subspace of a vector space R2/R3. The homework statement and equations were provided, and the attempt at a solution involved applying the three conditions for verifying a subspace. The conversation concluded with the asker understanding how to approach the problem.
  • #1
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Hey, this isn't for homework per se, but if anyone could lend me a hand figuring this out I'd appreciate it a lot!

Homework Statement



Determine whether Q is a subspace of R2/R3 in the following cases:

Homework Equations



Q = [tex]\{\left v = \left( v1, v2, 0 \right) | v1,v2 \in R \right\}[/tex]

Q = [tex]\{\left v = \left( v1, 0, 0 \right) | v1 \in R \right\}[/tex]

Q = [tex]\{\left v = \left( v1, v2 \right) \in R2 | v1 = v2 + 1, v1,v2 \in R \right\}[/tex]

The Attempt at a Solution



I honestly am not sure where I'm meant to start here. I know there are 3 conditions where a subspace may be valid; when it's equal to zero, If X and Y are in U, then X+Y is also in U
and If X is in U then aX is in U for every real number a.

How exactly am I meant to go about applying those rules? If someone could set me off on the right track that'd be awesome.
 
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  • #2
[tex]\{\left v = \left( v1, v2, 0 \right) | v1,v2 \in R \right\}[/tex]

(0,0,0) is clearly in Q

Let x = (x1,x2,0) and y =(y1,y2,0) be vectors in Q

then x+y = (x1+y1, x2+y2, 0) is also in Q

and ax = a(x1,x2, 0) = (ax1, ax2, 0) is in Q
 
  • #3
Tweet said:
Hey, this isn't for homework per se, but if anyone could lend me a hand figuring this out I'd appreciate it a lot!

Homework Statement



Determine whether Q is a subspace of R2/R3 in the following cases:

Homework Equations



Q = [tex]\{\left v = \left( v1, v2, 0 \right) | v1,v2 \in R \right\}[/tex]

Q = [tex]\{\left v = \left( v1, 0, 0 \right) | v1 \in R \right\}[/tex]

Q = [tex]\{\left v = \left( v1, v2 \right) \in R2 | v1 = v2 + 1, v1,v2 \in R \right\}[/tex]

The Attempt at a Solution



I honestly am not sure where I'm meant to start here. I know there are 3 conditions where a subspace may be valid; when it's equal to zero, If X and Y are in U, then X+Y is also in U
and If X is in U then aX is in U for every real number a.
To correct your terminology, there are 3 conditions for verifying that a subset U of a vector space V is a subspace of that vector space. 1) Zero is an element of U. The other two are fine.
Tweet said:
How exactly am I meant to go about applying those rules? If someone could set me off on the right track that'd be awesome.

See RandomVariable's reply.
 
  • #4
Cool, thanks very much guys. Makes sense now!
 

FAQ: Is Q a Subspace of R2 or R3?

1. What is a subspace?

A subspace is a subset of a vector space that satisfies the same vector space properties as the original space. This means that it contains the zero vector, is closed under vector addition and scalar multiplication, and is non-empty.

2. How do you determine if a set is a subspace?

To determine if a set is a subspace, you must check if it satisfies the vector space properties. This includes checking if the zero vector is in the set, if the set is closed under vector addition and scalar multiplication, and if the set is non-empty. If all of these conditions are met, then the set is a subspace.

3. Can a subspace be a line or a plane?

Yes, a subspace can be a line or a plane. In fact, a line or a plane is a common example of a subspace in a vector space. As long as the subset satisfies the vector space properties, it can be considered a subspace.

4. How does determining a subspace relate to linear independence?

Determining a subspace is closely related to linear independence. In order for a set of vectors to form a subspace, they must be linearly independent. This means that none of the vectors can be written as a linear combination of the others. Linear independence is an important concept in determining a subspace.

5. Can a subspace have more than one basis?

Yes, a subspace can have more than one basis. A basis for a subspace is a set of vectors that spans the subspace and is linearly independent. There can be multiple sets of vectors that satisfy these conditions and therefore can be considered as a basis for the same subspace.

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