Is Relativistic Mass Consistent in Inelastic Collisions?

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In summary: Normally this subject is treated through conservation of momentum in elastic collision. However, they introduce the Brehme diagram which allows for the analysis of collisions in only one dimension of space. The Brehme diagram is used to calculate the mass-ratio equation. It is difficult to decide whether the above condition is justified or not.
  • #1
snoopies622
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In section 8-2 of Sears and Brehme's "Introduction to the Theory of Relativity", the authors derive the formula for the "relativistic mass" of a particle in motion by analyzing a completely inelastic collision between identical objects from more than one frame of reference. I'm having a little trouble following it because their analysis relies heavily on a Brehme space-time diagram, which is a kind I'm not used to.

My question however is, is this even possible to do? In an inelastic collision the rest masses of the objects change, and nowhere in their analysis do I see this mentioned or factored into the equations. Also, when I try to analyze the collision myself - without using their diagram but with the same overall approach - I get a different (wrong) answer. I don't know if I'm making a mistake or if authors are somehow cheating.

I won't go into any of the mathematical details here in this first entry just in case someone out there already knows the answer to this question based on the information I've given, or already has the text.

Thanks.
 
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  • #2
snoopies622 said:
My question however is, is this even possible to do? In an inelastic collision the rest masses of the objects change, and nowhere in their analysis do I see this mentioned or factored into the equations.

Normally this subject is treated through conservation of momentum in elastic collision. See a very good treatment here
 
  • #3
Thanks, starthaus. Yes, I've seen that approach. What attracts me to the Sears and Brehme one is that it takes place in only one dimension of space instead of two. That's why I'm struggling to understand it.

Here's a little of the math.

They start by saying, suppose an object of mass B moving at velocity v strikes another object of mass A that is at rest. If the two objects stick together and then move with velocity V, then we shall define the ratio of the two masses in this way:

[tex]

\frac {m_A}{m_B} = \frac {v}{V} - 1

[/tex]

I see how this would work in classical mechanics, but I've never seen in used in relativistic mechanics, and I could be wrong but it does smell a little fishy to me.

Any thoughts?
 
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  • #4
snoopies622 said:
Thanks, starthaus. Yes, I've seen that approach. What attracts me to the Sears and Brehme one is that it takes place in only one dimension of space instead of two. That's why I'm struggling to understand it.

Here's a little of the math.

They start by saying, suppose an object of mass B moving at velocity v strikes another object of mass A that is at rest. If the two objects stick together and then move with velocity V, then we shall define the ratio of the two masses in this way:

[tex]

\frac {m_A}{m_B} = \frac {v}{V} - 1

[/tex]

I see how this would work in classical mechanics, but I've never seen in used in relativistic mechanics, and I could be wrong but it does smell a little fishy to me.

Any thoughts?

It is difficult for me to decide whether the above condition is justified or not. They seem to use as a starting point:

[tex](m_A+m_B)V=m_Bv[/tex]

This doesn't seem right since the masses seem to be the "relativistic" (ugly) masses. Obviously, the [tex]m_B[/tex] in LHS is not the same as the [tex]m_B[/tex] on the RHS since they encapsulate different [tex]\gamma[/tex] values. To wit:

[tex]m_{B-LHS}=m0_B*\gamma(V)[/tex]
[tex]m_{B-RHS}=m0_B*\gamma(v)[/tex]




So, it would seem that the proof has started on the wrong foot.


On the other hand, the proof on wiki is very clean, there are no errors.
 
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  • #5
snoopies622 said:
Also, when I try to analyze the collision myself - without using their diagram but with the same overall approach - I get a different (wrong) answer.

OK, I finally got the right answer using their approach, but I agree with you starthaus, that mass-ratio equation doesn't really make sense. I wonder why it works in this case then. Coincidence, perhaps. I suppose a deeper analysis would reveal the answer.
 
  • #6
Of course this raises the question, what is a good experimental way to define the ratio of two masses?
 
  • #7
snoopies622 said:
Of course this raises the question, what is a good experimental way to define the ratio of two masses?
Hmm... maybe something along the lines of "resistance to change in inertia". So apply a constant force to the masses, and see how their velocities change. Maybe that isn't good since if one is taking mass to no longer be intrinsic to the particle, then how could you know if the "intrinsic" quantities the force depend on aren't changing with velocity as well.

That is pretty close to the original idea of how they came up with the notion of "relativistic mass" in the first place. Since instead of F = (d/dt) mv, we have F = (d/dt) gamma m v.

Out of curiosity, in the book, what do they do with relativistic mass after bringing it up? Or are they just bringing it up for historical reasons?
 
  • #8
I haven't read ahead yet but just by skimming it looks like they use it to find the relativistic kinetic energy of a particle. Actually it looks like there's a lot of interesting stuff ahead, but those damned Brehme diagrams are on every page!
 

Related to Is Relativistic Mass Consistent in Inelastic Collisions?

1. What is the Sears, Brehme and momentum equation?

The Sears, Brehme and momentum equation, also known as the momentum transfer equation, is a fundamental equation in fluid mechanics that describes the conservation of momentum for a fluid flowing through a system. It is often used to analyze the flow of air or other gases through various structures and devices.

2. Who were Sears and Brehme?

Franklin Sears and Henry Brehme were American physicists who first developed the momentum transfer equation in the 1950s. They were studying the flow of air through jet engines and realized the need for a more comprehensive equation to describe the complex fluid dynamics involved.

3. How is the Sears, Brehme and momentum equation used in research and industry?

The Sears, Brehme and momentum equation is used in various fields such as aeronautics, meteorology, and chemical engineering to analyze and predict the behavior of fluids in different systems. It is also used in the design and optimization of various devices and structures, such as aircraft wings and wind turbines.

4. What are the assumptions made in the Sears, Brehme and momentum equation?

The Sears, Brehme and momentum equation makes several assumptions, including the fluid being incompressible, inviscid (no internal friction), and steady-state (no changes over time). It also assumes that the fluid is flowing through a system with no external forces acting on it, and that the flow is two-dimensional and irrotational.

5. Is the Sears, Brehme and momentum equation still relevant today?

Yes, the Sears, Brehme and momentum equation is still widely used in research and industry today. While it may not be applicable in all situations, it remains a foundational equation in fluid mechanics and is often used as a starting point for more complex analyses and models.

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