- #1
laminatedevildoll
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Am I doing this right? I'd appreciate any feedback.
Let T:U ---> v be an isomorphism. Show that T^-1: V----> U is linear.
i. T^-1(0) = 0
ii. T^-1(-V) = -T^-1(V)
T^-1(-0) = T^-1(0+0)
= T^-1(0) + T^-1(0)
T^-1(0) = 0
T^-1(-V) = T^-1((-1)V)
=(-1)T^-1(V)
= -T^-1(V)
If T[x,y,z] = [x-y, y-z, x+z]
Then T is one-to-one right?
How do I show that T is onto?
Let T:U ---> v be an isomorphism. Show that T^-1: V----> U is linear.
i. T^-1(0) = 0
ii. T^-1(-V) = -T^-1(V)
T^-1(-0) = T^-1(0+0)
= T^-1(0) + T^-1(0)
T^-1(0) = 0
T^-1(-V) = T^-1((-1)V)
=(-1)T^-1(V)
= -T^-1(V)
If T[x,y,z] = [x-y, y-z, x+z]
Then T is one-to-one right?
How do I show that T is onto?