Is the Commutator [P², Lx] in Quantum Mechanics Zero?

In summary, the conversation is about calculating the commutative [P^2,Lx] using the given equations. The person asking the question is trying to figure out if their attempt at the solution is correct or not, and is referencing an exercise from a book for context. The expert reminds them of a typo in their equations and asks if they have applied the changes to their solution.
  • #1
gfxroad
20
0

Homework Statement


Calculate the commutative
[P2,Lx]

Homework Equations


P2=P2x+P2y+P2z
[Py,Lx]=-iħPz
[Pz,Lx]=iħPy
[Px,Lx]=[Py,Ly]=[Pz,Lz]=0

The Attempt at a Solution


[P2,Lx]=[P2x+P2y+P2z,Lx]
=[P2x,Lx]+[P2y,Lx]+[P2z,Lx]
=Px[Px,Lx]+[Px,Lx]Px+Py[Py,Lx]+[Py,Lx]Py+Pz[Pz,Lx]+[Pz,Lx]Pz
=-iħ[Py+Py]+iħ[Pz+Pz]
=iħ[P2z+P2y]
 
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  • #2
First off, what is your question? Second off, your commutation relations are wrong. For example, [P2,L1]=-iħP3.
 
  • #3
Thanks, I was edited the given (miss-writing)
The question is written in the first step
Calculate the commutative [P^2,Lx]=?
 
  • #4
Yes, but what is the question you have about how to do this? You've fixed the typo, but you haven't applied the changes to your solution.
 
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  • #5
Please, I want to clear to me is the attempts is wrong or true.
Its an exercise (5.2) page 325 of Quantum Mechanic 2nd edition of Nouredine Zettili. The following is the link of the book.
https://ia601700.us.archive.org/6/items/QuantumMechanicsConceptsAndApplications2ndEdNouredineZettili/Quantum%20Mechanics%20-%20Concepts%20and%20Applications%20-%202ndEd%20-%20Nouredine%20Zettili.pdf
 
  • #6
As I said before, you've fixed the typos in your "Relevant Equations", but you haven't applied these changes to your solution.
 
  • #7
tman12321
I was putted the relevant equation directly at the attempt part in the third step of solution.
 
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FAQ: Is the Commutator [P², Lx] in Quantum Mechanics Zero?

What is the commutative property in quantum mechanics?

The commutative property in quantum mechanics refers to the fact that the order in which operators act on a system does not affect the final result. In other words, if two operators, A and B, are applied to a quantum state, the order in which they are applied does not change the outcome.

How does the commutative property affect measurements in quantum mechanics?

The commutative property has a significant impact on measurements in quantum mechanics. It allows us to measure observables, such as position or momentum, without affecting the state of the system. This is because the order of measurement does not change the outcome, so we can measure multiple observables simultaneously without interference.

Can the commutative property be violated in quantum mechanics?

No, the commutative property is a fundamental principle in quantum mechanics and cannot be violated. It is a necessary condition for the mathematical framework of quantum mechanics to work, and any attempt to violate it would lead to inconsistencies and contradictions.

How does the commutative property relate to Heisenberg's uncertainty principle?

The commutative property is closely related to Heisenberg's uncertainty principle. This principle states that certain pairs of observables, such as position and momentum, cannot be simultaneously known to arbitrary precision. This is because these observables do not commute, and therefore, measuring one affects the other.

Are there any real-world applications of the commutative property in quantum mechanics?

Yes, the commutative property has many real-world applications, particularly in quantum computing. The ability to measure multiple observables without interference allows for the development of quantum algorithms that can solve certain problems much faster than classical computers. It also has applications in quantum cryptography and quantum teleportation.

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