- #1
whitejac
- 169
- 0
Homework Statement
Homework Equations
d/dx
The Attempt at a Solution
d/dx (T) = d/dx(1/2mx'2) = mx''
d/dx(U) = d/dx(1/2kx2) = kx' ≠ kx
It's probably me who made an error because I know that that equation (2.3) is the one I should be getting, but I don't understand how they did it because potential energy relies on position, so the derivative has to be a velocity vector.