Is the Faraday Cage invulnerable?

In summary, a Faraday Cage shields its inside from static electric fields outside, but can be penetrated if the electric fields outside change fast enough. Filtering is necessary to keep external fields from coupling into the shielded enclosure.
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yoyopizza
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I was wondering how protective a Faraday Cage actually is, can it be overcome by sending more amperage onto the exterior or does that not matter? Also what would cause a Faraday cage to be ineffective, like would a cord powering the device inside render the cage useless? Thanks for your help!
 
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  • #2
A Faraday cage perfectly shields its inside from static electric fields outside. So if the outside electric fields change fast enough, they can penetrate the cage.

If the power cord radiates, then it can indeed generate electric fields inside the cage.
 
  • #3
Wait, so it can or cannot penetrate the shield, you described it as shielding perfectly and also being able to penetrate. How could it penetrate? What do you mean by "outside electric fields change fast enough" and by the power cord radiates? (im very new to this and do not understand most technical jargon, so please explain your answer so the laymen like me can understand you) :) thanks!
 
  • #4
yoyopizza said:
I was wondering how protective a Faraday Cage actually is, can it be overcome by sending more amperage onto the exterior or does that not matter? Also what would cause a Faraday cage to be ineffective, like would a cord powering the device inside render the cage useless? Thanks for your help!

yoyopizza said:
Wait, so it can or cannot penetrate the shield, you described it as shielding perfectly and also being able to penetrate. How could it penetrate? What do you mean by "outside electric fields change fast enough" and by the power cord radiates? (im very new to this and do not understand most technical jargon, so please explain your answer so the laymen like me can understand you) :) thanks!

Welcome to the PF.

Here is a link to a typical shielded enclosure company that will help you see what can be done:

http://ramseytest.com/index.php

You use metallic shielding to shield against E-fields and RF EM fields. You use ferrous shielding to shield against magnetic fields.

Because you often need "feedthroughs" to get power and signals through the walls of the shielded enclosure, you need to treat those feedthroughs with filtering to keep external fields from coupling into the shielded enclosures.

Is your question for general interest, or do you have a particular application in mind? There are lots of considerations to designing effective shielded encloures...
 
  • #5
yoyopizza said:
Wait, so it can or cannot penetrate the shield, you described it as shielding perfectly and also being able to penetrate. How could it penetrate? What do you mean by "outside electric fields change fast enough" and by the power cord radiates? (im very new to this and do not understand most technical jargon, so please explain your answer so the laymen like me can understand you) :) thanks!

It can penetrate by changing fast enough. So the faster it changes, the more it penetrates. You can see this in the link berkeman provided:

berkeman said:
http://ramseytest.com/index.php

The STE2200 on that site is described as:

Isolation
-100dB @ 1GHz
-90dB @ 3GHz
-80dB @ 6GHz

So you can see that the higher the frequency (ie. how fast the field changes), the less shielding the STE2200 provides.
 
  • #6
I think the lower attenuation at higher freqencies for those enclosures is because of the seams and apertures. For an ideal Faraday cage, I don't think there would be a change in attenuation versus frequency. But an ideal Faraday cage is not a practical thing -- who can use something with nothing going into or out of it?
 
  • #7
berkeman said:
I think the lower attenuation at higher freqencies for those enclosures is because of the seams and apertures. For an ideal Faraday cage, I don't think there would be a change in attenuation versus frequency. But an ideal Faraday cage is not a practical thing -- who can use something with nothing going into or out of it?

Yes, I mixed up real and ideal Faraday cages. Actually I had in mind that X-rays and gamma rays can penetrate metals because they aren't perfect conductors, but probably in the GHz range mentioned in the STE2200 specs, that's due more to the seams and apertures as you mentioned?
 
  • #8
So, I read that an airplane acts as a Faraday Cage and protects passengers form lightning strikes, but if that is true how do airplanes receive cell signal and WiFi? Also, there is no reason I ask this other than to satisfy curiosity. Would a computer act as a Faraday cage because of the metal encasing around it? Would it survive an electromagnetic pulse?
 
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yoyopizza said:
So, I read that an airplane acts as a Faraday Cage and protects passengers form lightning strikes, but if that is true how do airplanes receive cell signal and WiFi?

Via external antennas.
 
  • #10
So what could be done to strengthen a Faraday Cage? What makes it more resistant to high frequency waves?

Also, is there anything that would be different in designing a shield for electromagnetic pulses vs radio waves?
 
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  • #11
Why is it the wavelength of the wave that determines whether or not it can penetrate a Faraday Cage, instead of the amplitude?
 
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yoyopizza said:
So what could be done to strengthen a Faraday Cage? What makes it more resistant to high frequency waves?

Also, is there anything that would be different in designing a shield for electromagnetic pulses vs radio waves?

Do some web searches on "TEMPEST" "EMSEC".
 
  • #13
yoyopizza said:
Why is it the wavelength of the wave that determines whether or not it can penetrate a Faraday Cage, instead of the amplitude?

In general the electric field inside a metal enclosure depends on both the amplitude and the frequency of the external field. However, for electric fields of the same amplitude, different frequencies penetrate differently. The basic idea behind the Faraday cage is that when the external field is applied, electrons are free to move into new positions. Within the metal, the electrons in their new positions produce an electric field that cancels the external field. Each time the external field changes, the electrons must move to produce a new cancellation. In a real metal, the electrons take some time to move to the new positions. If in that time, the electric field changes before the electrons reach their new positions, then the external field will not be cancelled. This is one reason an electric field that changes fast enough will not be shielded in real metals.
 
  • #14
berkeman said:
Via external antennas.

Mobiles are still banned on most aircraft so unlikely they would provide an external antenna.

I believe the windows are big enough to prevent the aircraft being a faraday cage at mobile phone frequencies.
 
  • #15
CWatters said:
Mobiles are still banned on most aircraft so unlikely they would provide an external antenna.
Interesting. I haven't flown for a while, but I thought I remembered cell phones working once at altitude. I could be wrong though.

I believe the windows are big enough to prevent the aircraft being a faraday cage at mobile phone frequencies.
While on the ground that would probably be true. Once in the air, the antenna patterns of the cell towers would not cover airplanes.
 
  • #16
berkeman said:
While on the ground that would probably be true. Once in the air, the antenna patterns of the cell towers would not cover airplanes.

If that is true then how do I get cell signal on airplanes? And some airplanes do provide WiFi.
 
  • #17
yoyopizza said:
If that is true then how do I get cell signal on airplanes? And some airplanes do provide WiFi.

How do you think? If you worked for the airlines as an engineer, and they asked you to design a system to provide cell and WiFi connectivity on airborne airliners, how would you do it?
 
  • #18
Well, I would guess that the WiFi signal was coming from a satalite with a router inside the plane, and cell signal... I don't know if that could come from a satalite as well and have an antenna that brought signal inside the plane? that would be my best guess i really don't know.
 

FAQ: Is the Faraday Cage invulnerable?

What is a Faraday Cage and how does it work?

A Faraday Cage is an enclosure made of conductive material that is used to block electromagnetic fields. It works by redistributing the electric charge on its surface so that the electric fields cancel each other out, preventing any external electric fields from entering the enclosure.

Is a Faraday Cage completely invulnerable to all types of electromagnetic interference?

No, a Faraday Cage is not completely invulnerable. It is designed to block external electric fields, but it may not be able to block all types of electromagnetic interference. The strength and frequency of the electromagnetic field can also impact the effectiveness of the Faraday Cage.

Can a Faraday Cage protect against lightning strikes?

Yes, a well-constructed Faraday Cage can protect against lightning strikes. The electric charge from the lightning strike will be distributed on the surface of the cage and will not enter the enclosure, keeping the contents safe.

Can a Faraday Cage protect against a nuclear explosion or EMP?

Yes, a Faraday Cage can protect against a nuclear explosion or EMP (Electromagnetic Pulse). The metal enclosure will act as a shield and divert the energy from the explosion or pulse. However, the strength and proximity of the explosion or pulse can impact the effectiveness of the Faraday Cage.

Are there any materials that a Faraday Cage cannot protect against?

Yes, there are certain materials that a Faraday Cage may not be able to protect against, such as low-frequency magnetic fields or extremely high-frequency electromagnetic radiation. Additionally, if there are any gaps or holes in the enclosure, it may not be completely effective in blocking electromagnetic interference.

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