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HallsofIvy
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Yes, there exist many numbers "a" that will fit here. What about "prime"?Sievert said:Goldbach Conjecture is 2n = Prime (a+n)+ Prime (a-n), 1 is here prime
2 = (0+1)+(1-0)
4 = (1+2)+(2-1)
6 = (2+3)+(3-2)
8 = (3+4)+(4-3)
10= (2+5)+(5-2)
12= (1+6)+(6-1)
14 =(4+7)+(7-4)
16 =(3+8)+(8-3)
18 =(4+9)+(9-4)
20=(3+10)+(10-3)
22=(6+11)+(11-6)
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2n=(a+n)+(n-a)
Proof:
(a+n) = 2n+(a-n)=2n-(n-a)
q.e.d.[/QUOTE]
So, essentially, you are telling us that you do not know what a "proof" is.