Is the Intersection of T-Invariant Subspaces Always T-Invariant?

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In summary: Then when you say "Let W be their intersection", you take the intersection of all the W\alpha, for all \alpha in the index set. Then your argument will show that any element of that intersection is a T-invariant subspace.
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Homework Statement


Prove that the intersection of any collection of T-invariant subspaces of V is a T-invariant subspace of V.

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The Attempt at a Solution


Let W1 and W2 be T-invariant subspaces of V. Let W be their intersection.
If v[itex]\in[/itex]W, then v[itex]\in[/itex]W1 and v[itex]\in[/itex]W2. Since v[itex]\in[/itex]W1, T(v)[itex]\in[/itex]W1 & v[itex]\in[/itex]W2, T(v)[itex]\in[/itex]W2. Therefore T(v)[itex]\in[/itex]W.
For any x,y[itex]\in[/itex]W, x,y[itex]\in[/itex]W1 and x,y[itex]\in[/itex]W2, x,y[itex]\in[/itex]W and cx+y[itex]\in[/itex]W since W1 and W2 are subspaces.
Thus the intersection of any collection of T-invariant subspaces is a T-invariant subspace.

My answer was marked wrong. The grader's comment was to cross out "any" and replace it with "2". What I should have said? Was I supposed to explicitly point out that this applies from 2...n? :(
 
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Your grader is right. Your proof shows that given two invariant spaces W1 and W2, that their intersection is invariant.
Your proof does not shows that given n invariant subspaces W1, W2,..., Wn, that their intersection is invariant.
 
  • #3
In fact, the problem says "the intersection of any collection" so showing this for "n invariant subspaces" would not be sufficient. The collection does not have to be finite nor even countable.

Your proof will work nicely if you modify it so that instead of "W1" and "W2", you use [itex]W\alpha[/itex] where [itex]\alpha[/itex] is simply some label distinguishing the different sets- that is, [itex]\alpha[/itex] is just from some index set, not necessarily {1, 2}, nor even a set of numbers.
 

Related to Is the Intersection of T-Invariant Subspaces Always T-Invariant?

1. What is a T-invariant subspace?

A T-invariant subspace is a subset of a vector space that is closed under the linear transformation T. This means that when any vector in the subspace is operated on by T, the resulting vector is still within the subspace.

2. How are T-invariant subspaces useful in scientific research?

T-invariant subspaces are useful in scientific research because they allow for the simplification and analysis of complex systems. By identifying T-invariant subspaces, scientists can focus on understanding the behavior of a smaller subset of the system, which can provide insights into the overall behavior of the larger system.

3. How do you identify T-invariant subspaces?

T-invariant subspaces can be identified by finding the eigenvectors of the linear transformation T. These eigenvectors form a basis for the T-invariant subspace, and any vector in the subspace can be expressed as a linear combination of the eigenvectors.

4. Can a T-invariant subspace be more than one-dimensional?

Yes, a T-invariant subspace can have a dimension greater than one. In fact, the dimension of a T-invariant subspace can range from 0 (the trivial subspace) to the dimension of the entire vector space.

5. Are T-invariant subspaces unique?

No, T-invariant subspaces are not unique. For a given linear transformation T, there can be multiple T-invariant subspaces with different dimensions. Additionally, the same subspace can be T-invariant for different linear transformations.

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