Is the Riemann Zeta Function of 0 Infinity or -1/2?

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In summary, the Riemann-zeta function of 0 is supposed to be -1/2, but it is only defined for s>1 and can be extended analytically for s<=1. There are several formulas for s<1, which can be found in resources such as Wikipedia.
  • #1
dimension10
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The riemann zeta function of 0 is supposed to be -1/2. But isn't it infinity?

1/1^0 +1/2^0+1/3^0+1/4^0+...
1/1+1/1+1/1+1/1+...
1+1+1+1+...
infinity

But many sources claim that it is -1/2
 
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  • #2
dimension10 said:
The riemann zeta function of 0 is supposed to be -1/2. But isn't it infinity?

1/1^0 +1/2^0+1/3^0+1/4^0+...
1/1+1/1+1/1+1/1+...
1+1+1+1+...
infinity

But many sources claim that it is -1/2

Yes, you are correct, but the definition af the Riemann-zeta function as

[tex]\zeta (s)=\sum_{n=1}^{+\infty}{\frac{1}{n^s}}[/tex]

is only defined as s>1 (or in the complex case, as Re(s)>1). The Riemann-zeta function for [itex]s\leq 1[/itex] is defined as the "analytic continuation" of the above function. That is: the unique function that looks most like [itex]\zeta(s),s>1[/itex].
 
  • #3
micromass said:
is only defined as s>1 (or in the complex case, as Re(s)>1). The Riemann-zeta function for [itex]s\leq 1[/itex] is defined as the "analytic continuation" of the above function. That is: the unique function that looks most like [itex]\zeta(s),s>1[/itex].

The sum has infinitely many continuous extensions to the real line, but only one analytical extension to the complex plane.
 
  • #4
disregardthat said:
The sum has infinitely many continuous extensions to the real line, but only one analytical extension to the complex plane.

Well, a meromorphic extension really, since there is a pole in 1.
 
  • #5
micromass said:
Well, a meromorphic extension really, since there is a pole in 1.

You are right about that :redface:
 
  • #6
micromass said:
Yes, you are correct, but the definition af the Riemann-zeta function as

[tex]\zeta (s)=\sum_{n=1}^{+\infty}{\frac{1}{n^s}}[/tex]

is only defined as s>1 (or in the complex case, as Re(s)>1). The Riemann-zeta function for [itex]s\leq 1[/itex] is defined as the "analytic continuation" of the above function. That is: the unique function that looks most like [itex]\zeta(s),s>1[/itex].

Thanks, but is there a formula for s<1?
 
  • #8

FAQ: Is the Riemann Zeta Function of 0 Infinity or -1/2?

What is the Riemann Zeta Function?

The Riemann Zeta Function is a mathematical function that was introduced by mathematician Bernhard Riemann in the 19th century. It is defined as the infinite sum of the reciprocal of all positive integers raised to a certain power.

Is the Riemann Zeta Function of 0 Infinity or -1/2?

The Riemann Zeta Function of 0 is equal to -1/2. This is known as the Riemann Hypothesis, which has yet to be proven. However, many mathematicians believe it to be true based on extensive numerical evidence.

Why is the value of the Riemann Zeta Function of 0 important?

The value of the Riemann Zeta Function of 0 is important because it is connected to the distribution of prime numbers. The Riemann Hypothesis, if proven, would provide a deeper understanding of the distribution of prime numbers and potentially lead to new discoveries in number theory.

How is the Riemann Zeta Function of 0 calculated?

The Riemann Zeta Function of 0 is calculated using the Riemann zeta function formula, which is an infinite series. It can also be calculated using the Euler-Maclaurin formula, which is a more efficient method for large calculations.

What are the real world applications of the Riemann Zeta Function?

The Riemann Zeta Function has many applications in mathematics and physics. It is used in number theory, the study of prime numbers, and has connections to quantum mechanics and string theory. It also has applications in cryptography and coding theory.

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