Is the Schwarzschild Metric Always Applicable to Black Holes?

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The Schwarzschild metric is a solution to the Einstein Field Equations (EFE) for non-rotating, uncharged masses, including black holes, but it is not applicable below an object's surface due to its vacuum nature. While it accurately predicts the formation of a black hole if the object's surface lies within the Schwarzschild radius, real-world black holes are typically rotating. Therefore, the Kerr metric is preferred for describing these rotating black holes. The discussion emphasizes the limitations of the Schwarzschild metric in practical scenarios involving black holes. Understanding these distinctions is crucial for accurately modeling black hole physics.
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What do you put inside einstein field equation for black holes? Why is it that such black hole solution is not feasible?

Isnt the schwarzschild metric a solution for black holes? How is it not feasible?
 
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TimeRip496 said:
What do you put inside einstein field equation for black holes? Why is it that such black hole solution is not feasible?

Isnt the schwarzschild metric a solution for black holes? How is it not feasible?

Why are you saying that it's "not feasible"? The Schwarzschild metric is the solution to the EFE for (non-rotating, uncharged) masses, whether black holes or not. It doesn't apply below the surface of an object because it's a vacuum solution and below the surface isn't a vacuum, but if the object is dense enough that its surface lies inside the Schwarzschild radius, the Schwarzschild solution predicts that a a black hole will form, event horizon and all.

It it is true that any real world black hole formed by the collapse of a star will be rotating because the original star was rotating, and in that case you will want to use the Kerr metric instead of the Schwarzschild metric.
 

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