Is the Set [1;+∞[ x [1;+∞[ with the Operation (x;y)°(v;w) a Group?

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The set [1;+∞[ x [1;+∞[ with the operation (x;y)°(v;w) = (x+v-1; yw) is not a group due to issues with invertibility. Although closure, associativity, and identity have been proven, the inverse elements do not always lie within the set. Specifically, the calculations for the inverse yield values like 1/y and -x+2, which can fall outside the defined range when y > 1 or x = 2. Therefore, the operation does not satisfy all group properties. The conclusion is that this set with the given operation does not form a group.
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I have to find if the set [1;+∞[ x [1;+∞[ with the operation (x;y)°(v;w) = (x+v-1; yw) is a group

I have already proven Closure, associativity and Identity but I have some problems with invertibility :)

The neutral element that I have found is (1;1)

I did (x;y)°(x1;y1)= (1;1) and I have found x1=-x+2 and y1=1/y
The problem is that 1/y is not included in the set if y>1...

Any advice? Is it a group? Thank you :)
 
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Alv95 said:

Homework Statement


I have to find if the set [1;+∞[ x [1;+∞[ with the operation (x;y)°(v;w) = (x+v-1; yw) is a group


Homework Equations


I have already proven Closure, associativity and Identity but I have some problems with invertibility :)


The Attempt at a Solution


The neutral element that I have found is (1;1)
I did (x;y)°(x1;y1)= (1;1) and I have found x1=-x+2 and y1=1/y
The problem is that 1/y is not included in the set if y>1...

Any advice? Is it a group? Thank you :)

Use the forward slash "/" to close your tex tags.
It looks to me like you have answered your own question. Inverses don't seem to be there.
 
So it's not a group? :) The text of the homework that the teacher gave us seemed to imply that it was :)
 
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Alv95 said:
So it's not a group? :)

Indeed: it is not a group!
 
Thanks ;)
 
Just so you get it. The problem is that 1/y is not necessarily in our set. But that is not the only problem. There is a problem with -x+2 as well. That also doesn't necessarily lie in our set! Indeed, if x=2, then -x+2=0 and this is not in our set!
 
Alv95 said:
So it's not a group? :) The text of the homework that the teacher gave us seemed to imply that it was :)

C'mon. Show a little confidence in your work. Do you want to build a fence around it and insure it before you are willing to assert the result?
 
Well, I prefer to be sure about what I write especially if it is on a new topic that I have just learned at school ;) By seeking help and advices on the internet I hope to improve and strenghten my knowledge and thus be more confident. I didn't expect it to be a problem.
 
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Alv95 said:
Well, I prefer to be sure about what I write especially if it is on a new topic that I have just learned at school ;) By seeking help and advices on the internet I hope to improve and strenghten my knowledge and thus be more confident. I didn't expect it to be a problem.

It isn't a problem; I didn't mean to imply that it was. You nailed it on your first try. I was just trying to encourage you to be brave about what you've done. You do good work, so trust it.
 
  • #10
Thanks, I will :)
 

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