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jmjlt88
- 96
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I want to say yes. I am having trouble convincing myself though. Can anyone give me a very small nudge in the right direction? Thanks!
The dictionary order topology is a way of defining open sets in the Cartesian product of two topological spaces, such as R x R. In this topology, a basis for the open sets is given by intervals of the form (a,b) x (c,d), where the first coordinate is strictly between a and b, or equal to a or b if one of them is an endpoint, and the second coordinate is between c and d, or equal to c or d if one of them is an endpoint.
The dictionary order topology is different from other topologies in that it takes into account the ordering of the elements in the Cartesian product. This means that open sets in the dictionary order topology can look different from open sets in other topologies, even though they may contain the same points.
The dictionary order topology is a refinement of the standard topology on R x R. This means that every open set in the standard topology is also open in the dictionary order topology, but the converse is not necessarily true. The dictionary order topology is also finer than the standard topology, meaning that it contains more open sets.
Yes, the set {a} x (a,b) is open in R x R in the dictionary order topology. This is because it can be written as a union of basis elements, such as (a-ε,a+ε) x (a,b), for any ε>0. This is true for any point a in R and any interval (a,b) in R.
One example of a set that is not open in the dictionary order topology on R x R is the set (a,b) x [c,d). In this topology, the second coordinate must be strictly between c and d, so the point (b,d/2) is not contained in this set. However, any open set containing (b,d/2) would have to contain points with second coordinates greater than or equal to d, which contradicts the definition of the dictionary order topology.