- #1
jk22
- 729
- 24
Could it be said that since ##a=A(f(x))\sqrt{f(x)}##, with ##A(x)\in\{1,-1\}## then ##a^2=f(x)##,, that ##a## is the square root of ##f(x)## ?
In other words could the sign of the root depend on the argument inside it ?
Else it would have to be chosen by human free will and to be blocked for the rest of the calculation ?
In other words could the sign of the root depend on the argument inside it ?
Else it would have to be chosen by human free will and to be blocked for the rest of the calculation ?