- #1
karush
Gold Member
MHB
- 3,269
- 5
$\textsf{1) Evaluate the integral}$
\begin{align*}
I_1&=\int x \csc^2 6x \, dx\\
u&=6x\therefore du=dx\\
dv&=\csc^2(6x) \, dx \therefore v=-\frac{1}{6}\cot(6x) \\
u&=6x\therefore du=6 \, dx \\
I&=-\frac{1}{6} x\cot(6x)+\frac{1}{36}\int \cot(u) \, dx\\
&=\color{red}{
-\frac{1}{6} x\cot(6x)
+\frac{1}{36}\ln(|\sin36)|)}
\end{align*}
Ok I think this is correct, if so
saw another student use the tabular method to solve this
but couldn't see good enought to understand it
is that a lot easier.
\begin{align*}
I_1&=\int x \csc^2 6x \, dx\\
u&=6x\therefore du=dx\\
dv&=\csc^2(6x) \, dx \therefore v=-\frac{1}{6}\cot(6x) \\
u&=6x\therefore du=6 \, dx \\
I&=-\frac{1}{6} x\cot(6x)+\frac{1}{36}\int \cot(u) \, dx\\
&=\color{red}{
-\frac{1}{6} x\cot(6x)
+\frac{1}{36}\ln(|\sin36)|)}
\end{align*}
Ok I think this is correct, if so
saw another student use the tabular method to solve this
but couldn't see good enought to understand it
is that a lot easier.