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I have no college degree or any advanced formal training in physics, so this may be really, really obvious. Please be kind.
In GR, the amount by which time slows down on the surface of Earth compared to "empty" space is:
SQRT(1-2GM/(RC^2)).
For the surface of Earth that's 6.96 E-10 seconds per second.
In SR, the amount by which time slows down for an object falling from "infinity" to the surface of Earth is:
SQRT(1-V^2/C^2))
That's exactly the same answer.
Of course 2GM/R = V^2 (escape velocity squared) so this makes sense, for Earth and any other body.
Is the time dilation in GR also equal to same mass increase and Iength contraction as in SR?
I've looked for that answer and haven't found it.
Thanks for any replies.
In GR, the amount by which time slows down on the surface of Earth compared to "empty" space is:
SQRT(1-2GM/(RC^2)).
For the surface of Earth that's 6.96 E-10 seconds per second.
In SR, the amount by which time slows down for an object falling from "infinity" to the surface of Earth is:
SQRT(1-V^2/C^2))
That's exactly the same answer.
Of course 2GM/R = V^2 (escape velocity squared) so this makes sense, for Earth and any other body.
Is the time dilation in GR also equal to same mass increase and Iength contraction as in SR?
I've looked for that answer and haven't found it.
Thanks for any replies.