- #1
jpm
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Homework Statement
I'm trying to take the (two-sided, aka defined for all n) Z-transform of
[tex]x(n)=sin(Bn)[/tex]
Homework Equations
The Attempt at a Solution
What I tried to do was split x(n) into
[tex]x(n)=sin(Bn)u(n)+sin(Bn)u(-n-1)[/tex]
The Z transform of the first part of x(n) was found from a table. The z transform of the 2nd was found from the fact that the z transform of [tex]-sin(Bn)u(-n-1)[/tex] equals the z transform of [tex]sin(Bn)u(n)[/tex]
[tex]X(z)=\frac{z sin(B)}{z^2-2zcos(B)+1}-\frac{z sin(B)}{z^2-2zcos(B)+1}[/tex]
So the z transform is zero? Could this be?