Is there a mistake in this explanation of spherical coordinates?

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In summary, the author is using a substitution of z = cosθ in the Multivariable Calculus section for spherical coordinates, resulting in a negative sign before cosθ and the expression being equal to dz. This is a common technique in integration.
  • #1
leinadle
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The explanation for this is probably very trivial, but I am not seeing it. I'm reading through Ramamurti's "Basic Training in Mathematics" and in the Multivariable Calculus section for spherical coordinates he says

Using the fact that sinθdθ = dcosθ = dz

and then shows an integral. Shouldn't there be a negative sign before the cosθ? And how is this equal to dz?

Thanks in advance
 
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  • #2
leinadle said:
The explanation for this is probably very trivial, but I am not seeing it. I'm reading through Ramamurti's "Basic Training in Mathematics" and in the Multivariable Calculus section for spherical coordinates he says



and then shows an integral. Shouldn't there be a negative sign before the cosθ? And how is this equal to dz?

Thanks in advance
Yes, there should be a minus sign.
Apparently things started with this:

z = cosθ
dz = d(cosθ) = -sinθ dθ

It looks to me like the author is doing an ordinary substitution (z = cosθ) before carrying out the integration.
 
  • #3
Mark44 said:
Yes, there should be a minus sign.
Apparently things started with this:

z = cosθ
dz = d(cosθ) = -sinθ dθ

It looks to me like the author is doing an ordinary substitution (z = cosθ) before carrying out the integration.

Ah, I see. Thanks for the quick response!
 

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