- #1
Topher925
- 1,566
- 7
I've come across an complex integral that I just can't seem to figure out. Basically I need to integrate f(z) = 1/(z^6-1) around the circle |z+1|=1.
At first glance the radius of the circle must be zero in order to satisfy |z+1|=1 and therefore the function, f(z), is analytic in D so therefore the integral is zero. However, I've got the feeling this isn't correct. Am I doing something wrong?
At first glance the radius of the circle must be zero in order to satisfy |z+1|=1 and therefore the function, f(z), is analytic in D so therefore the integral is zero. However, I've got the feeling this isn't correct. Am I doing something wrong?