Is There an Algebraic Solution for 36=X^X?

  • Thread starter Freespader
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In summary, The conversation discussed an idea for an equation, 36=X^X, and the attempt to solve it, with the eventual discovery that it can be solved algebraically using the Lambert-W Function. The speaker also shared their implementation of the 'half intervall' function to find the zero of the equation in a given interval.
  • #1
Freespader
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I came up with an idea for an equation, which follows: 36=X^X. I tried solving it, but I couldn't. I found the graphically (3.15, if I recall correctly), but I want to know if there's a way to solve it algebraically.
 
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  • #2
Freespader said:
… I want to know if there's a way to solve it algebraically.

nope! :redface:
 
  • #3
Actually, you can, but you need to use the Lambert-W Function.
 
  • #4
Let f(x):=x[itex]^{x}[/itex] - 36, (f(x) is continuous, f(3.1) < 0, f(3.2) > 0) we can apply

the 'half intervall' function I implemented in my ARIBAS_W workbench, to find the zero of f(x)

in the intervall (3.1,3.2) as: 3.13564239388907368
 
  • #5

There is not a simple algebraic solution for this equation. It is known as a transcendental equation, meaning it cannot be solved using basic algebraic methods. However, it can be approximated using numerical methods such as the Newton-Raphson method or the bisection method. These methods involve using a computer or calculator to find a numerical solution. Alternatively, you can also use a graphing calculator to find the intersection of the two graphs of y=36 and y=x^x. I hope this helps!
 

FAQ: Is There an Algebraic Solution for 36=X^X?

How do I solve for x in 36=X^X?

To solve for x in this equation, you will need to use logarithms. Take the logarithm of both sides of the equation, then use the power rule to bring the exponent down. This will give you a linear equation that you can solve for x.

Can I use any base for the logarithm when solving for x in 36=X^X?

Yes, you can use any base for the logarithm as long as you use the same base for both sides of the equation. This will cancel out the logarithm and allow you to solve for x.

What if I have a different number instead of 36 in the equation X^X=n?

The steps for solving this type of equation will be the same. You will need to use logarithms and then solve for x. The only difference will be the specific numbers and variables that you are working with.

Can I use a calculator to solve for x in 36=X^X?

Yes, you can use a calculator to solve for x in this equation. You will need to use the logarithm function on your calculator to find the value of x.

Are there any other methods for solving X^X=n?

The most common method for solving this type of equation is using logarithms. However, there may be other methods depending on the specific equation you are working with. It is always helpful to try different approaches and see which one works best for your particular problem.

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