- #1
songoku
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- Homework Statement
- Nuclide A decays to nuclide B. Initially, there are ##1.29 \times10^9## nuclei of A and after some time the activity of A is 10 000 Bq. If the half life of A and B is 10 years and 10 hours respectively, find activity of B
- Relevant Equations
- ##A=\lambda N##
##t_{\frac 1 2}=\frac{ln~2}{\lambda}##
I found something I think does not make sense.
Decay constant of A:
$$\lambda_{A}=\frac{ln~2}{t_{\frac 1 2}}$$
$$=\frac{ln~2}{10\times 365 \times 24 \times 3600}$$
$$=2.2\times 10^{-9} / s$$
Initial activity of A = ##\lambda_{A} N_{\text{initial}}## = 2.2 x 10-9 x 1.29 x 109 = 2.84 Bq
Then after some time the activity becomes 10 000 Bq. How can the activity increase instead of decrease?
Is there something wrong with the question or something wrong with me?
Thanks
Decay constant of A:
$$\lambda_{A}=\frac{ln~2}{t_{\frac 1 2}}$$
$$=\frac{ln~2}{10\times 365 \times 24 \times 3600}$$
$$=2.2\times 10^{-9} / s$$
Initial activity of A = ##\lambda_{A} N_{\text{initial}}## = 2.2 x 10-9 x 1.29 x 109 = 2.84 Bq
Then after some time the activity becomes 10 000 Bq. How can the activity increase instead of decrease?
Is there something wrong with the question or something wrong with me?
Thanks