- #1
nukeman
- 655
- 0
is the math correct?
57.3 x d_o/d
d_o = size of object which is 1.392 x 10^6 km
d = distance to the object which is 147,056,800 km (Perihelion)
57.3 x 1.392 x10^6 (1,392,000) / 147,056,800km
= .54 Degrees
?
Thanks
57.3 x d_o/d
d_o = size of object which is 1.392 x 10^6 km
d = distance to the object which is 147,056,800 km (Perihelion)
57.3 x 1.392 x10^6 (1,392,000) / 147,056,800km
= .54 Degrees
?
Thanks