- #1
phy_
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A spider builds its web in a window frame that is lying on the ground. It is supported by four main strands. Calculate the force of tension in strand 4 assuming the web is stable. The tensions in the other three strands are as follows:
strand 1: 21 mN (20 degrees East of North)
strand 2: 16 mN (60 degrees East of South)
strand 3: 18 mN (40 degrees West of South)
if i solve y
T1 cos20(0.021N)
=0.019 N
T2 cos60(0.016N)
=0.008 N
T3 cos 40(0.018N)
=0.013 N
T4 y total 0.014
solve for x
sin20(0.021N)
=0.00718 N
sin60(0.016)
=0.013 N
sin(40)(0.018N)
=0.011N
T4 x total 0.0162
c squared = 0.0162 squared + 0.014 squared
c=0.0214
tan theta = 0.014/0.0162 = 0.0214 N40.8W degrees
is this correct?
strand 1: 21 mN (20 degrees East of North)
strand 2: 16 mN (60 degrees East of South)
strand 3: 18 mN (40 degrees West of South)
if i solve y
T1 cos20(0.021N)
=0.019 N
T2 cos60(0.016N)
=0.008 N
T3 cos 40(0.018N)
=0.013 N
T4 y total 0.014
solve for x
sin20(0.021N)
=0.00718 N
sin60(0.016)
=0.013 N
sin(40)(0.018N)
=0.011N
T4 x total 0.0162
c squared = 0.0162 squared + 0.014 squared
c=0.0214
tan theta = 0.014/0.0162 = 0.0214 N40.8W degrees
is this correct?