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I've found this site that states: "The surface gravity on Mars is only about 38% of the surface gravity on Earth." So a 100 lbs object will weigh about 38 lbs or a 45.359 kg will be on Mars 17.237 kg (converting 38 lbs in kg). So to find the Fg of Mars, I did this kind of equation:
[tex]
\frac{45.359 kg}{444.518 N} = \frac{17.237 kg}{X}
[/tex]
(444.518)(17.237) = (45.359)(X)
7662.156766 = 45.359X
[tex]
\frac{7662.156766}{45.359} = X
[/tex]
168.9225 N = X
-----------------------------------
Now that we know the weight of the object in Newtons on Mars' surface, then:
17.237 kg ÷ X = 168.9225 N
X = 0.10204876 N
Fgravity = 0.10204876 N
So the force of gravity on Mars surface is approximately 0.10204876 Newtons, right? The site that I found the information at is: [URL]http://coolcosmos.ipac.caltech.edu/cosmic_kids/AskKids/mars_gravity.shtml[/ur].
[tex]
\frac{45.359 kg}{444.518 N} = \frac{17.237 kg}{X}
[/tex]
(444.518)(17.237) = (45.359)(X)
7662.156766 = 45.359X
[tex]
\frac{7662.156766}{45.359} = X
[/tex]
168.9225 N = X
-----------------------------------
Now that we know the weight of the object in Newtons on Mars' surface, then:
17.237 kg ÷ X = 168.9225 N
X = 0.10204876 N
Fgravity = 0.10204876 N
So the force of gravity on Mars surface is approximately 0.10204876 Newtons, right? The site that I found the information at is: [URL]http://coolcosmos.ipac.caltech.edu/cosmic_kids/AskKids/mars_gravity.shtml[/ur].
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