Is This the Correct Method to Compute Flux Integral Over Cylinder Walls?

In summary, to compute the flux integral over a cylinder's walls oriented along the z axis, one approach is to use the Divergence Theorem by finding the divergence of the vector field \vec{F} and integrating it over the solid cylinder. Another approach is to split the cylinder into three pieces (top, bottom, and side) and sum the flux contributed from each piece. However, the latter approach may not be the most efficient method.
  • #1
IniquiTrance
190
0
To compute the flux integral over a cylinder's walls oriented along the z axis:

Can I do:

[tex]\int\int \vec{F}\cdot\nabla G(x,y,z) dA[/tex]

[tex]G(x,y,z) = r^{2}=x^{2}+y^{2}[/tex]

[tex]\nabla G = <2x, 2y, 0>[/tex]

[tex]\int\int \vec{F}\cdot <2x,2y,0> dA[/tex]

Is this a correct approach?
 
Physics news on Phys.org
  • #2
IniquiTrance said:
To compute the flux integral over a cylinder's walls oriented along the z axis:

Can I do:

[tex]\int\int \vec{F}\cdot\nabla G(x,y,z) dA[/tex]

[tex]G(x,y,z) = r^{2}=x^{2}+y^{2}[/tex]

[tex]\nabla G = <2x, 2y, 0>[/tex]

[tex]\int\int \vec{F}\cdot <2x,2y,0> dA[/tex]

Is this a correct approach?

Assuming a positive orientation, the easiest way to do it is by Divergence Theorem.

(1) Find the divergence of [tex]\vec{F}[/tex]

(2) Integrate this over the solid cylinder.

The other way is to split the cylinder into 3 pieces the Top, Bottom and Side and the sum the flux contributed from each piece.
 
  • #3
~Death~ said:
Assuming a positive orientation, the easiest way to do it is by Divergence Theorem.

(1) Find the divergence of [tex]\vec{F}[/tex]

(2) Integrate this over the solid cylinder.

The other way is to split the cylinder into 3 pieces the Top, Bottom and Side and the sum the flux contributed from each piece.

Thanks for the reply.

Yeah, I specifically want to solve it as a flux integral without the div theorem.

Also know how to split it up. Is this a proper way to compute it over the cylinder walls though?
 

FAQ: Is This the Correct Method to Compute Flux Integral Over Cylinder Walls?

What is a flux integral over a cylinder?

A flux integral over a cylinder is a mathematical concept used in physics and engineering to calculate the flow of a vector field through a cylindrical surface. It is essentially a measure of the amount of a vector field passing through a specific area of the cylinder.

How is the flux integral over a cylinder calculated?

The flux integral over a cylinder is calculated by first defining the vector field and the cylindrical surface. Then, the surface is divided into small sections, and the flux through each section is calculated. Finally, the flux through all sections is added together using a mathematical formula.

What is the significance of the flux integral over a cylinder?

The flux integral over a cylinder is significant because it allows us to determine the amount of a vector field passing through a specific area. This information is useful in various fields, such as fluid dynamics and electromagnetism, where understanding the flow of a vector field is important.

What are some real-life applications of the flux integral over a cylinder?

The flux integral over a cylinder has many real-life applications, including calculating the flow of air or water through a pipe, determining the strength and direction of magnetic fields, and analyzing the behavior of electric currents in conductors.

Are there any limitations or assumptions when using the flux integral over a cylinder?

There are a few limitations and assumptions when using the flux integral over a cylinder. First, it assumes that the vector field is constant over the surface of the cylinder. It also assumes that the cylinder is closed, meaning that there are no holes or openings in the surface. Additionally, it is important to consider the shape and orientation of the cylinder when using the flux integral, as it may affect the accuracy of the calculation.

Similar threads

Replies
2
Views
2K
Replies
4
Views
3K
Replies
6
Views
2K
Replies
15
Views
4K
Replies
2
Views
2K
Replies
11
Views
3K
Back
Top