- #36
PeterDonis
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objecta99 said:if looking from the ground clock, the jet must be moving away or toward at X velocity. If looking from the jet, the ground/clock must be moving away or toward at the very same X velocity.
Yes.
objecta99 said:We know, however, that one has a higher velocity than the other (and time distorts differently) with respect to a frame that is not rotating with the Earth.
I added the bold portion to make clear the mistake you are making; you are switching frames in mid-stream, so to speak. *Whenever* you use the word "velocity", you should *always* specify which frame it is relative to. Otherwise you will only confuse yourself (not to mention make it difficult for others to understand what you're saying).
objecta99 said:The frame that is "not" rotating with the Earth is the jet flying against the rotation.
No, it isn't; the jet flying westward is *not* at rest in a frame that is rotating with the earth. It is simply moving slower in that frame than the observer on the ground or the jet flying eastward.
objecta99 said:That's one of the two frames.
No, if we are going to be precise, there are *four* "frames" total that are relevant to this problem: the frame that is not rotating with the Earth, the rest frame of the jet flying westward, the rest frame of the observer on the ground (rotating with the Earth), and the rest frame of the jet flying eastward.
objecta99 said:There are 2 objects, the jet/clock and the ground/clock. Everything else is irrelevant. In one scenario the jet is flying with the rotation, in the other it is flying against the rotation.
As the experiment was actually done, it was one "scenario" with two jets in it, one flying eastward and one flying westward. I think it is clearer to just analyze it this way, including both jets.
objecta99 said:It is the case that the one jet has a higher velocity and the other a lower velocity, in relation TO the ground/clock.
In the actual experiment, both jets had velocities that varied with time. But if we are idealizing both jets as flying with constant velocity, we can just as easily idealize both jets as flying with the *same* velocity relative to the ground clock.
However, the real point is that the velocity relative to the ground clock is *not* the velocity that matters for understanding the difference in elapsed times; the velocity that matters for that is the velocity relative to the frame that is not rotating with the Earth (which is *not* the same as the frame of the ground clock).
objecta99 said:And when they meet, the clock represents differing slow downs between the jet/clock and ground/clock.
No, it represents one clock slowing down compared to the ground clock (the eastward-flying jet's clock), and one clock *speeding up* compared to the ground clock (the westward-flying jet's clock). This is because, once again, the velocity that matters is the velocity with respect to a frame that is not rotating with the Earth. Relative to that frame, the westward-flying jet moves slower than the ground clock, which in turn moves slower than the eastward-flying jet. That is what makes the westward-flying jet's clock run *faster* than the ground clock, and the eastward-flying jet's clock run slower.
Try re-thinking the experiment in the light of the above; hopefully it will help to clear things up.