- #1
zezima1
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Trying to teach myself contour integration, but I'm not so good at it. I want help with evaluating the closed integral:
∫sinθ/(a-sinθ)dθ from -[itex]\pi[/itex] to [itex]\pi[/itex]
So I substitute z= eiθ, and sinθ = -i/2(z-z-1) and dθ = -ie-iθdz
So our integral becomes:
∫-i/2(z-z-1)/(a+i/2(z-z-1) dz
Is this correct so far? If so, what do I do from this point? I suppose I want to find the order of the pole for this function?
∫sinθ/(a-sinθ)dθ from -[itex]\pi[/itex] to [itex]\pi[/itex]
So I substitute z= eiθ, and sinθ = -i/2(z-z-1) and dθ = -ie-iθdz
So our integral becomes:
∫-i/2(z-z-1)/(a+i/2(z-z-1) dz
Is this correct so far? If so, what do I do from this point? I suppose I want to find the order of the pole for this function?