Isospin conservation and pi-meson

[MathematicalPhysicist]

I am given this next question:
Show that the new resonance Z+[4430] which is too heavy to consist entirely of d and u quarks cannot be a meson (which constitues from a quark and an anti quark).

I am given that it's decay in a strong interaction to particles $$\psi',\pi^+$$
And I know that the first has isospin I=0 and the second I=1, and in strong interaction I is conserved, i.e Z+[4430] should have I=1 only, so if it were a meson it can only be composed of u and anti d or anti u and d, but from because of the remark it's not possible.

Am I correct here?

Thanks in advance.

 

[AndyW]

I would respond to this forum post by first acknowledging that the reasoning presented is correct. The new resonance Z+[4430] cannot be a meson because it violates the isospin conservation rule in strong interactions. This means that it cannot be composed of a quark and an anti-quark, as mesons are.

However, I would also mention that there are other types of particles that can have a spin of 1 and can decay to \psi' and \pi^+ without violating isospin conservation. One example is a tetraquark, which is composed of four quarks. Another possibility is a hybrid meson, which is a combination of a quark-antiquark pair and a gluon. So while it is correct to say that Z+[4430] cannot be a meson, it is important to consider other possibilities as well.

Additionally, as a scientist, I would also suggest looking at other experimental evidence and theoretical models to further understand the nature of Z+[4430]. This could include studying its decay patterns, mass spectrum, and production mechanisms, as well as considering different theoretical frameworks such as lattice QCD or effective field theories.

Overall, it is important to continue investigating and analyzing the properties of Z+[4430] in order to fully understand its nature and role in the Standard Model of particle physics.