Isothermal expansion of an ideal gas

In summary, one mole of monatomic ideal gas undergoes an isothermal expansion from an initial pressure (P) and volume (V) to a final pressure (2P) and volume (2V). Then, the gas undergoes an isochoric compression where the pressure increases from P/2 to 2P while the volume stays constant at 2V. The change in energy for this process is 0, the heat input is P x V x (ln2), the work output is also P x V x (ln2), and the change in entropy is R(ln2). To find the change in internal energy, one must use the equation \Delta U = Cv \Delta T and determine the Cv for this gas
  • #1
thezac11
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Homework Statement



One mole of monatomic ideal gas is taken from an initial pressure(P) and volume(V) to a final pressure(2P) and volume(2V). It goes from pressure=P and volume=V to pressure=P/2 and volume=2V through isothermal expansion and from there volume stays constant but the pressure goes to 2P from the previous P/2 and this path is through isochoric compression. The temperature remains constant.

-What is the change in energy of the process?
-What is the heat input?
-What is the work output?
-What is the change in entropy?


Homework Equations



change in energy = (heat in) - (work out)

change in entropy = heat in/temperature

Ideal gas law: PV=nRT, where n=amount of substance, R=constant, T=temp.

The Attempt at a Solution



I know the answers I just want to know how to get them. If you can explain the process I would greatly appreciate it. The final answers are:

-Change in energy = 0

-Heat input = P x V x (ln2)

-Work out = P x V x (ln2)

-Change in entropy = R(ln2)
 
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  • #2
thezac11 said:

Homework Statement



One mole of monatomic ideal gas is taken from an initial pressure(P) and volume(V) to a final pressure(2P) and volume(2V). It goes from pressure=P and volume=V to pressure=P/2 and volume=2V through isothermal expansion and from there volume stays constant but the pressure goes to 2P from the previous P/2 and this path is through isochoric compression. The temperature remains constant.

-What is the change in energy of the process?
I am not sure what this question is asking. There are three forms of energy: Work, Heat flow and internal energy.
The change in internal energy
What is the equation for [itex]\Delta U = ?[/itex].(Hint: it involves Cv). What is the Cv for this gas?

Determine the change in U in each step. There is no change in U in the first step (isothermal expansion) but there is a change in internal energy for the second step (isochoric heating). You will have to work out what that is.

-What is the heat input?
In the first step, there is no change in U. So what is the relationship between [itex]\Delta Q[/itex] and W for the first step? In the second step, what is the relationship between P and T if V is constant? If P increases by 4x what happens to T? What amount of heat is required to raise the temperature by that amount (hint: it involves Cv).

-What is the work output?
What is the expression for W in terms of P and change in V? What is the W in the first step? (hint: it involves an integral involving P and V and you have to substitute for P in terms of V and T in that integral) Is there any work done by the gas in the second step (isochoric)?

-What is the change in entropy?
Write out the expression for [itex]\Delta S[/itex] (hint: it involves Q and T and an integral)

What is the heat flow in the first step? What is the temperature? What is [itex]\Delta S[/itex]?

What is the heat flow in the second step? What is the relationship between dQ and dT? Put that into the integral and integrate.

AM
 

FAQ: Isothermal expansion of an ideal gas

1. What is isothermal expansion?

Isothermal expansion is a thermodynamic process in which an ideal gas expands at a constant temperature. This means that the internal energy of the gas remains constant and no heat is gained or lost during the expansion.

2. Why is isothermal expansion important?

Isothermal expansion plays a crucial role in many industrial processes, such as refrigeration and air conditioning, as well as in the functioning of internal combustion engines. It also helps in understanding the behavior of gases in various physical and chemical processes.

3. What is an ideal gas?

An ideal gas is a theoretical gas that follows the gas laws perfectly at all temperatures and pressures. It is assumed to have no intermolecular forces and the particles are considered to be point masses with no volume.

4. What is the equation for isothermal expansion of an ideal gas?

The equation for isothermal expansion of an ideal gas is given by: PV = constant, where P is the pressure, V is the volume, and the constant represents the temperature of the gas. This equation is known as Boyle's Law.

5. How does isothermal expansion differ from adiabatic expansion?

In isothermal expansion, the temperature remains constant while the volume and pressure change, whereas in adiabatic expansion, no heat is exchanged between the gas and its surroundings. This results in a change in temperature along with the change in volume and pressure.

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