- #1
bjnartowt
- 284
- 3
Homework Statement
With a Taylor series expansion of the well-behaved [itex]\rho ({\bf{x'}})[/itex] around [itex]{\bf{x'}} = {\bf{x}}[/itex], one finds the Taylor expansion of the charge density to be,
[itex]\rho ({\bf{x'}}) = \rho ({\bf{x}}) + {\textstyle{1 \over 6}}{r^2}{\nabla ^2}\rho + ...[/itex]
Homework Equations
The Attempt at a Solution
This proposed Taylor exapnsion looks correct, except for the 1/6 instead of the 1/2. What gives??