Joko's question at Yahoo Answers (r(t) perpendicular to r'(t))

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In summary, the tangent vector to the curve r(t) is always perpendicular to the curve itself, as shown by calculating the dot product of r(t) and r'(t) and obtaining a result of 0. This proves that the tangent vector is always perpendicular to r(t).
  • #1
Fernando Revilla
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Here is the question:

r (t) = tcos(t) i + tsin(t) j + sqrt(4 − t^2) k, 0<t<2 (should be less then equal to signs in the constraint)

Show, by calculation, that the tangent vector to this curve is always perpendicular
to r (t).

I have struggled to much with this question, not really sure where to start?

Here is a link to the question:

Please help, How to show if a tangent vector is perpendicular to r(t)? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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  • #2
Hello Joko103,

For all $t\in [0,2)$ we have $$r(t)=(t\cos t,t\sin t,\sqrt{4 − t^2})\\r'(t)=\left(\cos t-t\sin t\cos t,\sin t+t\cos t,\dfrac{-t}{\sqrt{4 − t^2}}\right)$$ Then, $$r(t)\cdot r'(t)=t\cos^2t-t^2\sin t\cos t+t\sin^2t+t^2\sin t\cos t-t=\\t(\cos^2t+\sin^2t)-t=t-t=0\Rightarrow r(t)\mbox{ is perpendicular to }r'(t)$$
 

Related to Joko's question at Yahoo Answers (r(t) perpendicular to r'(t))

1. What does the notation "r(t) perpendicular to r'(t)" mean?

The notation "r(t) perpendicular to r'(t)" means that the position vector r(t) is perpendicular to the velocity vector r'(t) at a given point in time. In other words, the direction of motion at that point is at a right angle to the direction of the position.

2. How is "r(t) perpendicular to r'(t)" related to motion?

The concept of "r(t) perpendicular to r'(t)" is related to motion because it describes the relationship between position and velocity. When the position and velocity vectors are perpendicular, it means that the object is moving in a circular path at that particular point in time.

3. Why is it important to understand "r(t) perpendicular to r'(t)" in physics?

Understanding "r(t) perpendicular to r'(t)" is important in physics because it helps us to analyze the motion of objects and understand their trajectory. It also allows us to calculate important quantities such as the speed, acceleration, and direction of motion of an object at a given point in time.

4. How does "r(t) perpendicular to r'(t)" relate to vectors?

"r(t) perpendicular to r'(t)" relates to vectors because both position and velocity are vector quantities. This means that they have both magnitude and direction. When the position and velocity vectors are perpendicular, it means that they have a dot product of zero, indicating that they are at right angles to each other.

5. Can "r(t) perpendicular to r'(t)" ever change?

Yes, "r(t) perpendicular to r'(t)" can change as the object moves and its position and velocity vectors change. At different points in time, the position and velocity vectors may no longer be perpendicular, indicating a change in the direction of motion of the object.

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