Jumping impulse physics homework

In summary: So 3461.53846154 is the net force, and 9.8 * 75 is the gravitational force, then the force exerted by the ground is just the sum of those two? 4196.5385?In summary, when jumping straight down, you can reduce the risk of injury by bending your knees upon landing. The average net force acting on a 75 kg man in a stiff-legged landing is 3461.53846154 N, while when he bends his knees, the average force is 4196.5385 N. The force of the ground on the man in both cases is the sum of the net force and the gravitational force acting on him.
  • #1
keemosabi
109
0

Homework Statement


When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75 kg man just before contact with the ground has a speed of 6.0 m/s.

(a) In a stiff-legged landing he comes to a halt in 1.5 ms. Find the average net force that acts on him during this time.
N
(b) When he bends his knees, he comes to a halt in 0.13 s. Find the average force now.
N
(c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b).
stiff legged landing
N

bent legged landing
N



Homework Equations





The Attempt at a Solution


I got part a, b and the first part of c. How is the second part of c different from the answer in b?
 
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  • #2


keemosabi said:

Homework Statement


When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75 kg man just before contact with the ground has a speed of 6.0 m/s.

(a) In a stiff-legged landing he comes to a halt in 1.5 ms. Find the average net force that acts on him during this time.
N
(b) When he bends his knees, he comes to a halt in 0.13 s. Find the average force now.
N
(c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b).
stiff legged landing
N

bent legged landing
N



Homework Equations





The Attempt at a Solution


I got part a, b and the first part of c. How is the second part of c different from the answer in b?
The anser you got in a and b should be the net force, which includes both gravity and the normal force of the ground acting on the man. To get the normal force of the ground only, both for in parts a and b, draw the FBD.
 
  • #3


PhanthomJay said:
The anser you got in a and b should be the net force, which includes both gravity and the normal force of the ground acting on the man. To get the normal force of the ground only, both for in parts a and b, draw the FBD.
I drew it so it would be just the normal force, 75 * 9.8? But it said that was wrong.

Edit: Or is it the net force plus the gravitational force?
 
  • #4


keemosabi said:
I drew it so it would be just the normal force, 75 * 9.8? But it said that was wrong.

Edit: Or is it the net force plus the gravitational force?
75*9.8 is the gravitational force acting on him, that is, his weight, acting down. The normal force is the force of the ground acting up on him. Since the net force is up, and the gravitational force is down, what's the normal force?
 
  • #5


PhanthomJay said:
75*9.8 is the gravitational force acting on him, that is, his weight, acting down. The normal force is the force of the ground acting up on him. Since the net force is up, and the gravitational force is down, what's the normal force?
So 3461.53846154 is the net force, and 9.8 * 75 is the gravitational force, then the force exerted by the ground is just the sum of those two? 4196.5385?
 

FAQ: Jumping impulse physics homework

1. What is jumping impulse in physics?

Jumping impulse in physics is a measure of the change in an object's momentum during a jump. It is calculated by multiplying the force applied during the jump by the time the force is applied.

2. How is jumping impulse related to jumping height?

According to the impulse-momentum theorem, the change in momentum of an object is equal to the impulse applied to it. Therefore, the greater the jumping impulse, the greater the change in momentum and the higher the jumping height.

3. How does mass affect jumping impulse?

The mass of an object is directly proportional to its momentum, so a greater mass will require a greater force and longer time to achieve the same jumping impulse as a lighter object. However, a heavier object may also have a stronger gravitational force, which can affect the height of the jump.

4. Can jumping impulse be increased?

Yes, jumping impulse can be increased by either increasing the force applied or increasing the time the force is applied. This can be achieved through techniques such as using a running start, bending the knees before jumping, or using a trampoline.

5. How is jumping impulse different from jumping force?

Jumping force is a measure of the force applied during a jump, while jumping impulse takes into account both the magnitude and duration of the force. Jumping impulse also takes into account the change in momentum, while jumping force does not.

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