- #1
genericusrnme
- 619
- 2
I've been reading through a book on relativity and I came across this
[itex]\mathcal{E}=p . v - L[/itex]
[itex]\mathcal{E} =\frac{m v}{\sqrt{1-\frac{v^2}{c^2}}}.v + m c^2\sqrt{1-\frac{v^2}{c^2}}[/itex]
I know this part well enough but then the book arrives at
[itex]\mathcal{E}=\frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}[/itex]
How did that happen?
All I can get is this
[itex]\mathcal{E} =\frac{m v^2}{\sqrt{1-\frac{v^2}{c^2}}} + m c^2\sqrt{1-\frac{v^2}{c^2}}\neq \frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}[/itex]
What am I doing wrong here?
Thanks in advance
[itex]\mathcal{E}=p . v - L[/itex]
[itex]\mathcal{E} =\frac{m v}{\sqrt{1-\frac{v^2}{c^2}}}.v + m c^2\sqrt{1-\frac{v^2}{c^2}}[/itex]
I know this part well enough but then the book arrives at
[itex]\mathcal{E}=\frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}[/itex]
How did that happen?
All I can get is this
[itex]\mathcal{E} =\frac{m v^2}{\sqrt{1-\frac{v^2}{c^2}}} + m c^2\sqrt{1-\frac{v^2}{c^2}}\neq \frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}[/itex]
What am I doing wrong here?
Thanks in advance