Just a quick question on the derivation of energy

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The discussion revolves around the derivation of energy in the context of relativity, specifically the equation \mathcal{E}=\frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}. The original poster is confused about how to simplify the equation \mathcal{E}=p . v - L to reach the final form. A participant suggests multiplying the second term by \frac{\sqrt{1-\frac{v^2}{c^2}}}{\sqrt{1-\frac{v^2}{c^2}}} to clarify the derivation. This advice helps resolve the confusion, leading to an acknowledgment of the mistake. The conversation highlights the importance of algebraic manipulation in understanding relativistic energy equations.
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I've been reading through a book on relativity and I came across this

\mathcal{E}=p . v - L
\mathcal{E} =\frac{m v}{\sqrt{1-\frac{v^2}{c^2}}}.v + m c^2\sqrt{1-\frac{v^2}{c^2}}

I know this part well enough but then the book arrives at

\mathcal{E}=\frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}

How did that happen?
All I can get is this

\mathcal{E} =\frac{m v^2}{\sqrt{1-\frac{v^2}{c^2}}} + m c^2\sqrt{1-\frac{v^2}{c^2}}\neq \frac{m c^2}{\sqrt{1-\frac{v^2}{c^2}}}

What am I doing wrong here?

Thanks in advance
 
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Multiply the second term by
\frac{\sqrt{1-\frac{v^2}{c^2}}}{\sqrt{1-\frac{v^2}{c^2}}}
and I think you'll find that it works.
 
Ah, thanks Parlyne
I feel like a tool now :L
 
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