- #1
Kudo Shinichi
- 109
- 1
Just wondering is the solution right?it is a 1D kinematic problem
An elevator ascends with an upward acceleration of 1.2m/s^2. At the instant its upward speed is 2.4 m/s, a loose bolt drops from the ceiling of the elevator 2.7m from the floor. Calculate the time of flight of the bolt from ceiling to floor and the distance its has fallen relative to the elevator shaft.
s1 = 2.4t - (1/2)gt^2
s2 = 2.4t + (1/2)(1.2)t^2
2.7= -2.4t + (1/2)gt^2 + 2.4t + (1/2)(1.2)t^2
2.7 = (1/2)[9.8 + 1.2]t^2
2.7 = 5.5t^2
t = √(2.7/5.5) = 0.7 seconds
s1 = 2.4(0.7) - (1/2)(9.8)(0.7)^2
s1 = -0.724 meters
Just wondering is the answer right or not.
Homework Statement
An elevator ascends with an upward acceleration of 1.2m/s^2. At the instant its upward speed is 2.4 m/s, a loose bolt drops from the ceiling of the elevator 2.7m from the floor. Calculate the time of flight of the bolt from ceiling to floor and the distance its has fallen relative to the elevator shaft.
The Attempt at a Solution
s1 = 2.4t - (1/2)gt^2
s2 = 2.4t + (1/2)(1.2)t^2
2.7= -2.4t + (1/2)gt^2 + 2.4t + (1/2)(1.2)t^2
2.7 = (1/2)[9.8 + 1.2]t^2
2.7 = 5.5t^2
t = √(2.7/5.5) = 0.7 seconds
s1 = 2.4(0.7) - (1/2)(9.8)(0.7)^2
s1 = -0.724 meters
Just wondering is the answer right or not.