Katie's Question: Find f(2) & f'(2) of Tangent Line y=4x-5

Therefore, in summary, to find f(2) and f'(2) for the given equation of the tangent line y=4x-5 at the point where a=2, we first use the fact that the instantaneous slope of the function must match the slope of the tangent line at the point of tangency. Then, we use the equation of the tangent line to find the value of f(2). Thus, f'(2)=4 and f(2)=3.
  • #1
MarkFL
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Here is the question:

If an equation of the tangent line to the curve y=f(x) at the point where a=2 is...?


y=4x-5, find f(2) and f'(2)

Please walk me through this question step by step.

I have posted a link there to this topic so the OP can see my work.
 
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  • #2
Hello Katie,

Consider the following diagram, showing the function $f(x)=x^2-1$ and its tangent line $y=4x-5$:

View attachment 1403

As you can see, the instantaneous slope of the function must match the slope of the tangent line at the point of tangency, and the value of the function at that point must be equal to the value of the tangent line at that point since they touch there. Hence, we must have:

\(\displaystyle f'(2)=\frac{d}{dx}(4x-5)=4\)

\(\displaystyle f(2)=y(2)=4(2)-5=3\)
 

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FAQ: Katie's Question: Find f(2) & f'(2) of Tangent Line y=4x-5

What is the equation for the tangent line in this problem?

The equation for the tangent line is y = 4x - 5.

How do you find f(2) in this problem?

To find f(2), we substitute 2 in for x in the given equation, y = 4x - 5. This gives us f(2) = 4(2) - 5 = 3.

What is the meaning of f(2) in this problem?

f(2) represents the value of the function at x = 2, or the value of the y-coordinate of a point on the tangent line when x = 2.

How do you find f'(2) in this problem?

To find f'(2), we take the derivative of the given function, y = 4x - 5, which gives us f'(x) = 4. Then, we substitute 2 in for x in the derivative to get f'(2) = 4.

What is the meaning of f'(2) in this problem?

f'(2) represents the slope of the tangent line at the point where x = 2. It shows the rate of change of the function at that point.

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