- #1
shounakbhatta
- 288
- 1
Hello,
While dealing with Kepler's 2nd.law, when calculating the area of the triangle which sweeps out:
Area of a triangle = 1/2 base x height
Now, we know dθ = dx/r (where dx = arc length, r=radius)
So, dx= rdθ
So, area of a triangle = 1/2 base(rdθ) x height(h)
Is this correct?
Thanks
While dealing with Kepler's 2nd.law, when calculating the area of the triangle which sweeps out:
Area of a triangle = 1/2 base x height
Now, we know dθ = dx/r (where dx = arc length, r=radius)
So, dx= rdθ
So, area of a triangle = 1/2 base(rdθ) x height(h)
Is this correct?
Thanks