Kim's Questions on Babylonian Method for Estimating Square Roots

[MarkFL]

Here are the questions:

Can someone please help me everytime I turn these in I get them wrong.?

1.Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.

2. Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?

3. Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?

4. If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?

I have posted a link there to this thread so the OP can view my work.

 

[MarkFL]

Re: Kim's questions at Yahoo! Answers regarding thethe Babylonian method for estimating square roots

Hello Kim,

The Babylonian method for approximating square roots is the recursive method given by:

Given:

\(\displaystyle x_0\approx\sqrt{k}\)

Then:

\(\displaystyle x_{n+1}=\frac{x_n^2+k}{2x_n}\)

where $k$ is the number for which we are approximating the square root.

So, armed with this formula, let's now answer the given questions:

1.) Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.

We will use 15 digits of precision here since it is not stated how many iterations to carry out:

\(\displaystyle x_0=11.5\)

\(\displaystyle x_1\approx11.4021739130435\)

\(\displaystyle x_2\approx11.4017542587143\)

\(\displaystyle x_3\approx11.4017542509914\)

\(\displaystyle x_4\approx11.4017542509914\)

Thus, with 15 digits of accuracy, we may state:

\(\displaystyle \sqrt{130}\approx11.4017542509914\)

2.) Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?

The next result here is approximately:

\(\displaystyle x_1=\frac{10.7262^2+115}{2\cdot10.7262}\approx10.7238055620816\)3.) Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?

The next result here is:

\(\displaystyle x_1=\frac{7.8^2+58}{2\cdot7.8}=7.6\overline{179487}\)

4.) If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?

The next result here is:

\(\displaystyle x_1=\frac{8^2+75}{2\cdot8}=8.6875\)