Kinematic Equations for a Rocket with Constant Acceleration: Homework Help

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In summary, the problem is asking for the final height of a rocket that starts at rest and accelerates straight upward with a constant net acceleration until its fuel runs out at time t_1. The equation y = Vi(t) + 1/2*a*t^2 is not sufficient, as the rocket will continue to go up after fuel exhaustion. The correct equation is H = .5(a)t^2 + (.5*a^2*t^2)/g, taking into account the additional distance traveled after fuel depletion.
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physstudent1
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Homework Statement



A Rocket initially at rest on the ground accelerates straight upward from rest with constant net acceleration a, until time t_1 where fuel is exhausted.

Homework Equations





The Attempt at a Solution



I thought that putting these values into the kinematic equation

y = Vi(t) + 1/2*a*t^2 would be good but the answer is not 1/2(a)t^2 it is

H = .5(a)t + (.5*a^2*t^2)/g
 
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  • #2
What is the problem asking for? Final height of the rocket? If so, remember that the rocket will still go up for a while after the fuel is exhausted, adding another distance to the one you have found. What's the initial velocity and what's the acceleration for the second part of this problem?
 
  • #3
yes

yes it is asking for final height thank you I did not think of it still going up after running out of fuel I was thinking of it falling back down immediatly
 
  • #4
physstudent1 said:

Homework Statement



A Rocket initially at rest on the ground accelerates straight upward from rest with constant net acceleration a, until time t_1 where fuel is exhausted.

Homework Equations





The Attempt at a Solution



I thought that putting these values into the kinematic equation

y = Vi(t) + 1/2*a*t^2 would be good but the answer is not 1/2(a)t^2 it is

H = .5(a)t^2 + (.5*a^2*t^2)/g
see typo in red, now continue per Chi Meson's hint above.
 

FAQ: Kinematic Equations for a Rocket with Constant Acceleration: Homework Help

What are the kinematic equations?

The kinematic equations are a set of mathematical formulas that describe the relationship between an object's position, velocity, acceleration, and time. These equations are used to analyze the motion of objects in one, two, or three dimensions.

What is the difference between displacement and distance?

Displacement is the change in an object's position from its starting point to its ending point, and it is measured in a specific direction. On the other hand, distance is the total length of the path an object traveled, and it is measured in a scalar quantity.

How do I use kinematic equations to solve problems?

To solve a problem using kinematic equations, you first need to identify the known values, such as initial and final positions, initial velocity, and acceleration. Then, choose the appropriate kinematic equation based on the known values and the unknown value you are trying to find. Finally, plug in the known values and solve for the unknown value.

What are the units of measurement for kinematic equations?

The units of measurement for kinematic equations vary depending on the specific equation being used. However, distance and displacement are typically measured in meters (m), velocity in meters per second (m/s), acceleration in meters per second squared (m/s^2), and time in seconds (s).

Can kinematic equations be used for objects with changing acceleration?

Yes, kinematic equations can be used for objects with changing acceleration. In this case, the average acceleration is used in the equations, which is the change in velocity divided by the change in time. However, if the acceleration is constantly changing, more complex equations, such as calculus, may be needed to accurately describe the motion.

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