Kinematic Problem: How Long to Reach Half Speed in a Fluid?

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In summary, the problem involves finding the time it takes for a marble to reach half its initial speed in a certain fluid. The acceleration equation is given by -3.00V^2 for v>0 and the initial speed is 1.50 m/s. Using the equation Vf=Vi + a(t) and A=(Vf-VI)/t, separation of variables is used to solve the first ODE. After integrating, the time is found to be 0.25 seconds.
  • #1
bjon-07
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Hi all, can some one please help me on this problem;

The acceleration of a marble in a certain fluid is proportional to the speed of the marbles, and is given (in SI units) by a= -3.00V^2 for v>0. If it enters this fluid with a speed of 1.50 m/s, how long will it take for the marble to reach half its intial speed.


I have released that

Vf=Vi + a(t)

.75=1.5+ a(t)
-.15=a(t)


and that A=(Vf-VI)/t

I am stuck after this. Please help me.
 
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  • #2
Do you calculus??This problem involves solving a first ODE through separation of variables...

Daniel.
 
  • #3
I am still stock on this problem. I have tryed using separation of variables but it just leads me in a circle.
 
  • #4
[tex]\frac{dv}{dt} = -3 v^2[/tex]
[tex]-\frac{1}{3 v^2} dv = dt[/tex]
Integrate!
 
  • #5
I can't beilve I did not see that :eek: LOL, its soo easy. Thank you for your help.
 

FAQ: Kinematic Problem: How Long to Reach Half Speed in a Fluid?

What is a tricky kinematic problem?

A tricky kinematic problem is a physics problem that involves the motion of objects without considering the causes of the motion. These problems typically require solving for unknown variables such as displacement, velocity, and acceleration using equations of motion.

What makes a kinematic problem challenging?

Kinematic problems can be challenging because they often involve multiple variables and require a deep understanding of the equations of motion and how to apply them. Furthermore, they may involve complex scenarios such as objects moving with changing velocities or in multiple dimensions.

How do you approach solving a tricky kinematic problem?

To solve a tricky kinematic problem, it is important to first identify the known and unknown variables and select the appropriate equation(s) of motion to use. Then, plug in the known values and solve for the unknown variable(s). It is also helpful to draw a diagram or use visual aids to better understand the problem.

Can you provide an example of a tricky kinematic problem?

Sure, here is an example: A ball is thrown upward with an initial velocity of 20 m/s. How high does it go before falling back down? This problem involves using the equation h = (v^2 - u^2)/2a, where h is the maximum height, v is the final velocity (0 m/s), u is the initial velocity (20 m/s), and a is the acceleration due to gravity (-9.8 m/s^2).

What are some common mistakes to avoid when solving kinematic problems?

One common mistake is using the wrong equation or incorrectly plugging in values. It is important to carefully read the problem and double check your calculations. Another mistake is forgetting to pay attention to the direction of motion, which can result in incorrect signs for velocity and acceleration values. Additionally, it is important to consider the physical limitations of the problem, such as objects cannot have negative displacement or velocity unless otherwise specified.

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