- #36
Satvik Pandey
- 591
- 12
Tanya Sharma said:Hello Chet
Isn't the velocity of cat always directed towards the mouse in the OP ?
What is OP?
Tanya Sharma said:Hello Chet
Isn't the velocity of cat always directed towards the mouse in the OP ?
I don't understand the second equation. Yes, the tangential velocity of the cat is ##v_{t, C} = r\omega_{C} = r \omega_{M} = ?## Sub in what you got for the angular speed of the mouse earlier on. {t,C} stands for tangential velocity of the cat and M is a label for the mouse.Satvik Pandey said:At a distance 'r' from center tangential velocity is rω or rV/R.
Right idea, but make the correction above in this formula.So, [itex]\frac{dr}{dt}[/itex]=√(V^2-(rv/R)^2).
You want the time it takes for the cat to reach R=28 having started at R=0. So you know the limits for R numerically. Your bounds for t are right. You just need to fix the integrand and then perform the integration.After some algebraic calculation I found this-
∫dx/[itex]\sqrt{R^{2}-r^{2}}[/itex]=[itex]/\frac{V}{R}[/itex]∫dt. Upper and lower limits of LHS is R and 0 respectively. Upper and lower limits of RHS is T and 0 respectively.
I just replaced ω.Here V is the velocity of mouse and R is 28cm(radius).I did this for calculating ω earlier in this discussion.CAF123 said:I don't understand the second equation. Yes, the tangential velocity of the cat is ##v_{t, C} = r\omega_{C} = r \omega_{M} = ?## Sub in what you got for the angular speed of the mouse earlier on. {t,C} stands for tangential velocity of the cat and M is a label for the mouse.
Satvik Pandey said:What is OP?
Ah okay, I misread the notation. So, V/R = 1/7. Sub this into your expression for the radial speed and the integral.Satvik Pandey said:I just replaced ω.Here V is the velocity of mouse and R is 28cm(radius).I did this for calculating ω earlier in this discussion.
.
Maybe it would help if I started to set up the version of the problem that I'm thinking of. Let R and θM be the polar coordinates of the mouse at some particular time t, and let r and ΘC be the polar coordinates of the cat at the same time t. The velocity of the cat is equal to V (a constant speed) times a unit vector in the direction from r,ΘC to R,θM. Note, that in this version of the problem, ΘC≠θM (except initially).Tanya Sharma said:Thanks Chet .
I am having difficulty in interpreting whether the pursuer’s velocity given in similar type of problems is radial velocity or instantaneous velocity .When the question says that the pursuer is always heading towards the target ,doesn’t it mean that the velocity given is instantaneous velocity ?
Here are two similar type of questions .
Q 1. A boy is on a boat, at a distance H from the shore, when he sees a girl (at the point on the shore where the distance is measured) running with a constant velocity u parallel to the shore. At that time, he moves towards her, with a speed v, in such a way, that the point of the boat is always pointed at the girl (so his vector is always pointing her way). Find the time of their meeting.
Q 2. Point A moves uniformly with velocity v so that the vector v is continually "aimed" at point B which in its turn moves rectilinearly and uniformly with velocity u < v. At the initial moment of time v is perpendicular to u and the points are separated by a distance l. How soon will the points converge?
What is your opinion regarding the velocity v given in the problems ? Do you think that the velocity v given in both the problems are the radial velocity or the instantaneous velocity ?
Chestermiller said:Maybe it would help if I started to set up the version of the problem that I'm thinking of. Let R and θM be the polar coordinates of the mouse at some particular time t, and let r and ΘC be the polar coordinates of the cat at the same time t. The velocity of the cat is equal to V (a constant speed) times a unit vector in the direction from r,ΘC to R,θM. Note, that in this version of the problem, ΘC≠θM (except initially).
Please tell me if this makes any sense so far.
ehild said:In the OP, v is the magnitude of velocity, that is, speed.
ehild
Tanya Sharma said:I am having difficulty in interpreting whether the pursuer’s velocity given in similar type of problems is radial velocity or instantaneous velocity .When the question says that the pursuer is always heading towards the target ,doesn’t it mean that the velocity given is instantaneous velocity ?
Tanya Sharma said:Here are two similar type of questions .
Q 1. A boy is on a boat, at a distance H from the shore, when he sees a girl (at the point on the shore where the distance is measured) running with a constant velocity u parallel to the shore. At that time, he moves towards her, with a speed v, in such a way, that the point of the boat is always pointed at the girl (so his vector is always pointing her way). Find the time of their meeting.
Tanya Sharma said:Q 2. Point A moves uniformly with velocity v so that the vector v is continually "aimed" at point B which in its turn moves rectilinearly and uniformly with velocity u < v. At the initial moment of time v is perpendicular to u and the points are separated by a distance l. How soon will the points converge?
Tanya Sharma said:What is your opinion regarding the velocity v given in the problems ? Do you think that the velocity v given in both the problems are the radial velocity or the instantaneous velocity ?
Yes.Tanya Sharma said:Does the attached picture correctly represents the setup ?
I would have drawn it a little differently, with the angles measured from the x - axis, and the mouse running counterclockwise. But this is OK too.The brown vector represents the instantaneous velocity V of cat.Pink radial velocity Vr and green transverse velocity VT .
Chestermiller said:Are you interested in working on this problem? The formulation of the problem should be interesting and instructive; the equations may not have an analytic solution, however.
Tanya Sharma said:Sure
But first I would let Satvik finish his original problem .I have already derailed the thread :shy:.After he completes the problem I will get back to you .
Thanks Chet .