- #1
Jim Alexandridis
- 2
- 1
- Homework Statement
- two small boxes of rectangular parallelepiped shape are launched simultaneously against each other, with velocities of meters 𝑢1=𝑢 and 𝑢2=2𝑢, from positions A and B of a straight and horizontal trajectory 𝑂𝑥 lying in a plane. The distance between them is 𝛢𝛣=𝑠 and the coefficient of friction between each body and the surface is μ. Boxes will collide if:
a)u≥2√(μgs)/3
b)u≥1√(μgs)/3
c)u≥2√(μgs)/5
d)u≥3√(μgs)/5
This problem was on an greek physics competition on 10th grade and there is a disagreement about the answer, so i would like your opinion depending on my answer
- Relevant Equations
- Kinematics:
V=v0+at
Dx=v0t+1/2at²
Smax=v²/2a
The distance covered by the first box is :s1max=v²/2|a|=v²/2μg where a=-μg by second newtons law
Similarly S2max=(2v)²/2|a|=4v²/2μg
It gas to be s1max+s2max≥S => v²/2a +4v²/2a ≥s => 5v²≥2aS =>v²≥ 2μgS/5=> v≥√(2μgs/5)
But this is in the possible solution, am I wrong somewhere? I appreciate your help
Similarly S2max=(2v)²/2|a|=4v²/2μg
It gas to be s1max+s2max≥S => v²/2a +4v²/2a ≥s => 5v²≥2aS =>v²≥ 2μgS/5=> v≥√(2μgs/5)
But this is in the possible solution, am I wrong somewhere? I appreciate your help