Kinematics problem from a competition: Will the 2 sliding boxes collide?

In summary, the problem involves determining whether two boxes sliding down an inclined plane will collide. By analyzing their positions and velocities as functions of time, considering factors such as the angle of the incline and initial conditions, one can calculate the trajectory of each box. If their paths intersect at the same time, a collision occurs; otherwise, they slide past each other without contact. The solution requires understanding kinematic equations and applying them accurately to predict the motion of each box.
  • #1
Jim Alexandridis
2
1
Homework Statement
two small boxes of rectangular parallelepiped shape are launched simultaneously against each other, with velocities of meters 𝑢1=𝑢 and 𝑢2=2𝑢, from positions A and B of a straight and horizontal trajectory 𝑂𝑥 lying in a plane. The distance between them is 𝛢𝛣=𝑠 and the coefficient of friction between each body and the surface is μ. Boxes will collide if:
a)u≥2√(μgs)/3
b)u≥1√(μgs)/3
c)u≥2√(μgs)/5
d)u≥3√(μgs)/5

This problem was on an greek physics competition on 10th grade and there is a disagreement about the answer, so i would like your opinion depending on my answer
Relevant Equations
Kinematics:
V=v0+at
Dx=v0t+1/2at²
Smax=v²/2a
The distance covered by the first box is :s1max=v²/2|a|=v²/2μg where a=-μg by second newtons law
Similarly S2max=(2v)²/2|a|=4v²/2μg
It gas to be s1max+s2max≥S => v²/2a +4v²/2a ≥s => 5v²≥2aS =>v²≥ 2μgS/5=> v≥√(2μgs/5)
But this is in the possible solution, am I wrong somewhere? I appreciate your help
 
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  • #2
Hi @Jim Alexandridis and welcome to PF.

The first box travels distance ##s_1=\dfrac{u^2}{2\mu g}##
The second box travels distance ##s_2=\dfrac{(2u)^2}{2\mu g}=\dfrac{4u^2}{2\mu g}=4s_1.##
The two boxes together travel distance ##s_1+s_2=5s_1=\dfrac{5u^2}{2\mu g}##
So what must be true for a collision to take place?

Sometimes multiple choice problems are not very well constructed.
 
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  • #3
kuruman said:
Hi @Jim Alexandridis and welcome to PF.

The first box travels distance ##s_1=\dfrac{u^2}{2\mu g}##
The second box travels distance ##s_2=\dfrac{(2u)^2}{2\mu g}=\dfrac{4u^2}{2\mu g}=4s_1.##
The two boxes together travel distance ##s_1+s_2=5s_1=\dfrac{5u^2}{2\mu g}##
So what must be true for a collision to take place?

Sometimes multiple choice problems are not very well constructed.
Isn’t that the same as the OP did in post #1?
 
  • #4
haruspex said:
Isn’t that the same as the OP did in post #1?
Yes. It's reassurance to a new user that when you're right, you're right.
 
  • #5
I believe that for the collision to happen it has to be :

##S_{1}+S_{2}\ge S##
 
  • #6
Jim Alexandridis said:
I believe that for the collision to happen it has to be :

##S_{1}+S_{2}\ge S##
That is correct. As you already posted, this condition leads to $$u \geq \sqrt{\frac{2\mu~g~s}{5}}$$which is not one of the options (a) - (d). What you can do with this information is up to you. It ranges from doing nothing to bringing it to the attention of someone who is in a position to improve the quality control of exams like this.
 
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  • #7
kuruman said:
That is correct. As you already posted, this condition leads to $$u \geq \sqrt{\frac{2\mu~g~s}{5}}$$which is not one of the options (a) - (d). What you can do with this information is up to you. It ranges from doing nothing to bringing it to the attention of someone who is in a position to improve the quality control of exams like this.
It might be a "copy/paste" issue. For example, in some other forum, I've just posted in LaTeX:
1712846272189.png

but after "edit and save" it has been converted to this:

1712846529653.png
 

FAQ: Kinematics problem from a competition: Will the 2 sliding boxes collide?

What is the basic concept of the kinematics problem involving sliding boxes?

The basic concept involves analyzing the motion of two boxes sliding on a surface, typically considering their initial positions, velocities, and accelerations. The goal is to determine whether the boxes will collide as they move over time.

How do I determine the initial conditions of the sliding boxes?

To determine the initial conditions, you need to know the initial positions, velocities, and accelerations of both boxes. This information is usually provided in the problem statement and is essential for calculating their future positions over time.

What equations are used to analyze the motion of the boxes?

The primary equations used are the kinematic equations, which relate position, velocity, acceleration, and time. The most common equation is: s = ut + (1/2)at², where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time. These equations allow you to calculate the position of each box at any given time.

How can I find out if the boxes will collide?

To determine if the boxes will collide, you need to set their position equations equal to each other and solve for time. If you find a valid time where both boxes occupy the same position, they will collide; if not, they will slide past each other without colliding.

What factors can affect the outcome of the collision?

Several factors can affect the outcome, including the initial velocities and accelerations of the boxes, the distance between them at the start, and any external forces acting on them, such as friction or air resistance. Additionally, if the boxes have different masses, this may also influence their motion if external forces are considered.

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