Kinetic Energy from Point A to B: Electron Volts

In summary, the potential difference between points a and b is +510 volts. A helium nucleus, which contains 2 neutrons and 2 protons, is electrically neutral. Using the formula E = K + U and the conservation of energy, we can find the change in kinetic energy of a charge of +2e as it moves from point a to b, which is equivalent to the potential difference of +510 volts. This results in a kinetic energy of 510 eV (electron volts) for the particle after accelerating from rest at point a to b. It is recommended to refer to the post titled "Electric Potential & Kinetic Energy" for similar problem-solving methods.
  • #1
gekdvb
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point a is at a potentiall of +290...point b is at potential of -220...helium nucleus contains 2 neutrons and 2 protons...neutrons are electrically neutral...what kinetic energy does particle have after accelerating from rest at point a to b...in electron volts
 
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  • #2
You should really show some working...

I think this is how you should go about it.

First, E = K + U. Then use conservation of energy, to find delta K, then use the kinetic energy work theorem.
 
  • #3
gekdvb said:
point a is at a potentiall of +290...point b is at potential of -220...helium nucleus contains 2 neutrons and 2 protons...neutrons are electrically neutral...what kinetic energy does particle have after accelerating from rest at point a to b...in electron volts
The potential difference between a and b is the energy/unit charge: ie. the energy that a unit charge gains in moving from a to b. The energy that a charge of e gains in moving through a potential difference of 1 volt is 1 eV. So what is the energy that a +2e charge gains in moving from a to b?

AM
 
  • #4
Look at the post called "Electric Potential & Kinetic Energy " (just above yours). The methods for solving the problems are very similar...
 
  • #5
gekdvb said:
point a is at a potentiall of +290...point b is at potential of -220...helium nucleus contains 2 neutrons and 2 protons...neutrons are electrically neutral...what kinetic energy does particle have after accelerating from rest at point a to b...in electron volts

take a look at this thread

https://www.physicsforums.com/showthread.php?t=61631
 

FAQ: Kinetic Energy from Point A to B: Electron Volts

What is kinetic energy?

Kinetic energy is the energy an object possesses due to its motion.

What is the relationship between kinetic energy and electron volts?

Electron volts (eV) are a unit of energy commonly used in the field of physics, particularly in the study of atoms and subatomic particles. One electron volt is equivalent to the amount of kinetic energy gained by an electron when it is accelerated through a potential difference of one volt. In other words, one eV is equal to 1.602 x 10^-19 joules (J).

How do you calculate the kinetic energy of an object in electron volts?

To calculate the kinetic energy of an object in electron volts, you can use the formula KE = 0.5mv^2, where m is the mass of the object in kilograms and v is the velocity of the object in meters per second. Once you have calculated the kinetic energy in joules, you can convert it to electron volts by dividing by 1.602 x 10^-19.

What is the significance of using electron volts to measure kinetic energy?

Using electron volts to measure kinetic energy allows for more precise calculations in the study of subatomic particles and atoms. Since these particles have very small masses and velocities, measuring their kinetic energy in joules would result in very small numbers. Electron volts provide a more convenient and practical unit for these types of calculations.

Can kinetic energy be converted into electron volts?

Yes, kinetic energy can be converted into electron volts by dividing the value in joules by 1.602 x 10^-19. Similarly, electron volts can be converted into joules by multiplying by 1.602 x 10^-19.

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