- #1
xcmntgeek
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Homework Statement
Point A is at a potential of +230 V, and point B is at a potential of -140 V. An -particle is a helium nucleus that contains two protons and two neutrons; the neutrons are electrically neutral. An -particle starts from rest at A and accelerates toward B. When the -particle arrives at B, what kinetic energy (in electron volts) does it have?
hence:
Change in potential=370 Volts
Homework Equations
Change in potential= -work/q
and
1e- moving through one volt of potential= 1.6e-19 Joules
The Attempt at a Solution
He= 2 protons = 2 (1.6e-19 coulombs)= 3.2e-19c
(370 Volts)(3.2e-19c)= 1.184e-16
Of course, this isn't right or I wouldn't be posting this. My ideas for where I've gone astray:
-the charge (in coulombs) of He is different than 3.2e-19
-The answer asks for the kinetic energy, but I thought eV was a measure of Potential Electric Energy?