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sudipmaity
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Homework Statement
When a 7 3 Li nucleus is bombarded with protons α particles emerge.Calculate the kinetic energy of the alpha particle assuming the kinetic energy of the bombarding proton to be negligible. Given M (7 3 Li)=7.016004a.m.u. M (p)=1.007826a.m.u and M (α)=4.002603a.m.u.
Homework Equations
7 3 Li + 1 1H --> 24 2He
Q = (M Li + MH -2Mα)931.5MeV...1
Kα=n= [MαQ + Kp(Mα - mp)]/2Mα...2
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The Attempt at a Solution
Using equation 1 Q=(7.016004+1.007826- 2×4.002603) 931.5 =17.35MeV
It is given that Kp~0 so Kα= Q/2 =8.675MeV
What do you people think about my solution methods used? The numerical values are matching approximately with the given answers in the textbook by the way.
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