Kinetic energy of alpha particle in cockroft walton experiment.

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The discussion focuses on calculating the kinetic energy of an alpha particle produced when a lithium-7 nucleus is bombarded by protons, with the kinetic energy of the protons considered negligible. The user successfully applied the relevant equations, determining the Q value to be 17.35 MeV and subsequently calculating the alpha particle's kinetic energy to be 8.675 MeV. There is a brief inquiry about the necessity of a second equation used in the calculations, which is deemed unnecessary by other participants. The solution aligns closely with textbook values, indicating accuracy in the calculations. Overall, the discussion highlights the application of nuclear reaction principles to derive kinetic energy values.
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Homework Statement


When a 7 3 Li nucleus is bombarded with protons α particles emerge.Calculate the kinetic energy of the alpha particle assuming the kinetic energy of the bombarding proton to be negligible. Given M (7 3 Li)=7.016004a.m.u. M (p)=1.007826a.m.u and M (α)=4.002603a.m.u.

Homework Equations


7 3 Li + 1 1H --> 24 2He
Q = (M Li + MH -2Mα)931.5MeV...1

Kα=n= [MαQ + Kp(Mα - mp)]/2Mα...2
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The Attempt at a Solution


Using equation 1 Q=(7.016004+1.007826- 2×4.002603) 931.5 =17.35MeV
It is given that Kp~0 so Kα= Q/2 =8.675MeV
What do you people think about my solution methods used? The numerical values are matching approximately with the given answers in the textbook by the way.

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Sure, looks good.

What does equation 2 mean? It is not necessary anyway.
 

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