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Drstevebrule
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Kinetic Friction Problem Needs Help!
A truck is traveling at constant acceleration. A box of mass 80kg rests in the bed of the truck. The Kinetic Friction between the bed and the box is 0.5. After traveling for 3 seconds the box falls off the back of the truck, what is the distance the box traveled?
F=ma
F friction = Uk(Mg)
Kinematic equations.
a=Ukg
a=.5(10)
a=5
D=.5(at^2)
D=.5(45)
D=22.5
Yet this distance, 22.5 meters, isn't even close to 4 multiple choice answers given on the test. The highest distance being 5 meters... what am I missing here?
Homework Statement
A truck is traveling at constant acceleration. A box of mass 80kg rests in the bed of the truck. The Kinetic Friction between the bed and the box is 0.5. After traveling for 3 seconds the box falls off the back of the truck, what is the distance the box traveled?
Homework Equations
F=ma
F friction = Uk(Mg)
Kinematic equations.
The Attempt at a Solution
a=Ukg
a=.5(10)
a=5
D=.5(at^2)
D=.5(45)
D=22.5
Yet this distance, 22.5 meters, isn't even close to 4 multiple choice answers given on the test. The highest distance being 5 meters... what am I missing here?